Since the discriminant given has a value that is greater than zero, hence the roots of the quadratic equation are real and distinct.
<h3>Discriminant of a quadratic equation</h3>
Quadratic equation is an equation that has a leading degree of 2. The discriminant is used to determine the nature of the equation
If D > 0 , the roots of the quadratic equation are real and distinct.
If D < 0 , the roots of the quadratic equation are complex
Since the discriminant given has a value that is greater than zero, hence the roots of the quadratic equation are real and distinct.
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Answer:
step 1. y - y1 = m(x - x1). this is the equation given a point and a slope.
step 2. find the slope m. m = (y2 - y1)/(x2 - x1) = (4 - (-4))/(0 - 2) = 8/-2 = -4.
step 3. y - (-4) = -4(x - 2) ; y + 4 = -4x + 8.
step 4. y = -4x + 4.
#1 is true. The term they have in common is y with an invisible coefficient in-front of the second y term
#2 has zero like terms. 15 has no variable, and the other terms have different variables.
#3 has two like terms, that’s 9 and 8 which add to equal 17. The answer is 3x + 17 aka D.
#4 has two like terms, the numbers with the variable ‘n’. 4n + 7n = 11n. Your answer is 11n + 12 aka D
so the ODE is indeed exact and there is a solution of the form 
. We have
With 
, we have
so
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