Answer:
II. One and only one solution
Step-by-step explanation:
Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One and only one solution. III. Many solutions.
Let assume the equation is given as;
x + 3y = 11 .... 1
x - y = -1 ....2
Using elimination method
Subtract equation 1 from 2
(x-x) + 3y-y = 11-(-1)
0+2y = 11+1
2y = 12
y = 12/2
y = 6
Substitute y = 6 into equation 2:
x-y = -1
x - 6 = -1
x = -1 + 6
x = 5
Hence the solution (x, y) is (5, 6)
<em>Hence we can say the equation has One and only one solution since we have just a value for x and y</em>
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Answer:
x = 82°
y = 59°
z = 39°
Step-by-step explanation:
∠x = 1/2(134° + 30°) = 82°
∠z = 180° - 59° - 82° = 39°
arc DF = 2(39°) = 78°
arc DB + arc DF = 134° + 78° = 212°
draw a diameter down from point B to the opposite side of the circle, call that point P:
arc BDP = 180°
(arc BDF) 212° - 180° = 32° (arc PF)
∠PBG = 1/2(32°) = 16°
∠DEB = 1/2(134°) = 67°
∠DBE = 180° - 59° - 67° = 54°
(∠DBE) 54° - (∠z) 39° + (∠PBG) 16° = (∠PBE) 31°
y = 90°- 31° = 59°
Answer:
D. 10
Step-by-step explanation:
Given f(x)=3x-8
f(6)=3(6)-8
f(6)=18-8
f(6)=10
I worked it out and I got south Africa
-3x<9. The way to figure this out is to divide by -3 to get x by itself. Remember, when dividing by a negative, you need to flip the inequality sign.
x>-3 is your answer.
I hope this helps!