The reciprocal of 1/5 is 5.
Reciprocals are numbers than when multiplied equal a product of 1. In this question, 1/5 * 5 = 1. An easy trick for finding reciprocals is flipping a fraction.
Hope this helps!!
Answer:x=3/2 or -1
Step-by-step explanation:
Answer:
(x-2), (x+2), (3x-5)
Step-by-step explanation:
Factors of 3: ±1, ±3
Factors of 20: ±1, ±2, ±4, ±5, ±10, ±20
Possible factors of the polynomial: ±1, ±2, ±3, ±4, ±5, ±10, ±20, .... (there's a lot more but you probably do not need to list them all)
Pick a number to divide the polynomial by (I picked 2)
(3x³-5x²-12x+20)÷(x-2) = 3x²+x-10
So (x-2) is a factor of f(x) = 3x³-5x²-12x+20
Factor 3x²+x-10 = (3x-5)(x-2) these are the other factors of f(x) = 3x³-5x²-12x+20
The inverse of the function f(x) = 4(x-3)² + 2 is 
The given function is:
f(x) = 4(x - 3)² + 2
To find the inverse of the function:
Make x as the subject of the formula

Replace x by
and replace f(x) by x

Therefore, the inverse of the function is:

Learn more here: brainly.com/question/17285960
Okay so to do the sqrt(75) you see if there are hidden squares. Split it to be the sqrt(25) and sqrt(3) then simplify. In the end, you get 5sqrt(3). Hope this helps!