Answer:
p-value = 0.369
Step-by-step explanation:
Test of hypothesis which has its the alternative hypothesis as Ha:μ1−μ2≠0 is a two tailed test. Therefore, P-value for a two-tailed test with test statistic t≈−0.90 and the number of degrees of freedom = 208
P-value = 2 X P( t(208) < - 0.90)
= 2 X 0.1846
= 0.369
Parallel lines will have the same slope, but different y int
y = -3/2x + 8....slope = -3/2....y int = 8
(I) 3x + 2y = 10
2y = -3x + 10
y = -3/2x + 5....slope = -3/2, y int = 5....this IS parallel
(II) 2x - 3y = 9
-3y = -2x + 9
y = 2/3x - 3...slope = 2/3, y int = -3....is not parallel
(III) 6x + 4y = 28
4y = -6x + 28
y = -3/2x + 7...slope = -3/2, y int = 7....this IS parallel
(IV) 3x - 2y = 8
-2y = -3x + 8
y = 3/2x - 4...slope = 3/2...y int = -4...this is not parallel
solution is : I and III
Answer:
0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x
Step-by-step explanation:
Given the data in the question;
sample size n = 28
slope of the least squares regression line of y on x or sample estimate = 0.0623
standard error = 0.0224
95% confidence interval
level of significance ∝ = 1 - 95% = 1 - 0.95 = 0.05
degree of freedom df = n - 2 = 28 - 2 = 26
∴ the equation will be;
⇒ sample estimate ± ( t-test) ( standard error )
⇒ sample estimate ± (
) ( standard error )
⇒ sample estimate ± (
) ( standard error )
⇒ sample estimate ± (
) ( standard error )
{ from t table; (
) = 2.055529 = 2.056
so we substitute
⇒ 0.0623 ± ( 2.056 )( 0.0224 )
Therefore, 0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x
Answer:
i'd say it's x=6
Step-by-step explanation:
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