Answer:
x = 12 cm
Step-by-step explanation:
The product of lengths from the secant intersection point to the "near" and "far" circle intersection points is the same for both secants. When one "secant" is a tangent, the lengths to the circle intersection points are the same (so their product is the square of the tangent segment length).
8^2 = 4·(4 +x) . . . . . . measures in centimeters
16 = 4 +x . . . . . . divide by 4
12 = x . . . . . . . . . subtract 4
1 should be b and 2 should be a
Polynomials are set of expressions with variables that are usually used in operations.
*2x^2 +3x-2
2x^4+3x^3(2x^3+2x)=4x^7+4x^5+6x^6+6x^4
*(^ is the raised exponent)
Refer to the diagram shown below.
Let the distance that Sassoon travels is d miles.
Let his average speed be x mph.
The time of travel is from 1 p.m. to 4 p.m., which is 3 hours.
Therefore
3x = d (1)
The distance that Archer travels is (d + 300) miles.
The time of travel is from 9 a.m. to 4 p.m., which is 7 hours.
The average traveling speed is (x + 20) mph, therefore
7(x + 20) = d + 300
That is,
7x + 140 = d + 300
7x = d + 160 (2)
Subtract (1) from (2).
7x - 3x = d + 160 - d
4x = 160
x = 40 mph (Sassoon's average speed)
x+20 = 60 mph (Archer's average speed)
From (1), obtain d = 120 mi
Answer:
Archer's speed is 60 mph.
Sassoon's speed is 40 mph.
The difference means subtract
89.4 - 13.621 = 75.779