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raketka [301]
3 years ago
11

Tyler used 17.04 gallons of gas. Maria used 6.2 times as many gallons of gas as Tyler. How many gallons of gas did Maria use?

Mathematics
1 answer:
Vesnalui [34]3 years ago
8 0
In that problem you will have to multiply, we know that Tyler used 17.04 gallons of gas, and that Maria used 6.2 times as many gallons of gas. So we are going to multiply 17.04 x 6.2 and the answer is 105.648, so Maria used 105.648 gallons of gas.
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Riley used a drawing to divide . He made groups of 12 with 1 left over. Hoy many groups did he make?
Yakvenalex [24]

Step-by-step explanation:

Here important information is missing. That is total number of divide.

However, it is given that riley made groups of 12 with 1left over from total number of divide. So, total number of divides on the drawing must be a multiple of 12 +1. It can be any number like 12n+1, where n is an integer. Then we ca find total number of group.  

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Suppose that water is being pumped into a trough. the trough is $$15 feet long, and every cross section of the trough is an equi
Dovator [93]
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Harding and Jack found that 8 percent of their number was 72. What was their number?
Aneli [31]
I do believe that the answer is 900. 
Steps:
I first set up a proportion, with 8/100 and 72/x (x being the number we are trying to find) 
As I was taught, you multiply 100 by 72, which equals 7,200.
Then, I divided 7,200 by 8, which gave me 900.
This is what the proportion process should have looked like:
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If the quadrilateral below is a rectangle, find the missing measures. Round to one decimal place.
Katarina [22]

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3 0
2 years ago
M men and w women seat themselves at random in m+w seats arranged in a row. find the probability that all the women will be adja
WINSTONCH [101]

The <em>correct answer</em> is:


\frac{(m+1)!w!}{(m+w)!}


Explanation:


We want all <em>w</em> women to be seated together. There are <em>w</em>! ways to do this.


Since all women are seated together, we consider the as 1 block to be seated with the men.


There are <em>m</em>! ways of arranging the men. However, we also have the 1 block of women to seat; this makes (<em>m</em>+1)! ways to seat the men and block of women.


There are (<em>m</em>+<em>w</em>)! ways to arrange all of the men and women.


This makes our probability

\frac{(m+1)!w!}{(m+w)!}.


For example, if there are 4 men and 3 women:

There are 3! = 6 ways to seat the women together. This makes 1 block of women.


There are 4! = 24 ways to seat the men together. Taking this with the block of women, we have (4+1)! = 5! = 120 ways to seat the men and block of women.


There are (4+3)! = 7! = 5040 ways to arrange 7 people.


This makes our probability 120(6)/5040 = 720/5040.

8 0
3 years ago
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