Lateral surface area of the prism = 920 in²
Total surface area of the prism = 1180 in²
Solution:
Length of the prism = 13 in
Width of the prism = 10 in
Height of the prism = 20 in
Lateral surface area of the prism = 2(l + w)h
= 2(13 + 10) × 20
= 2(23) × 20
= 920 in²
Lateral surface area of the prism = 920 in²
Total surface area of the prism = Lateral area + 2lw
= 920 + 2 × 13 × 10
= 920 + 260
Total surface area of the prism = 1180 in²
Hence Lateral surface area of the prism = 920 in²
Total surface area of the prism = 1180 in²
Answer/step-by-step explanation
The soldier at point P lie on a parabola because he determined his position and distances from towns A and B through measurement of the difference in timing (phase) of radio signals received from the two towns.
This analysis of the signal time difference gives the difference in distance of the soldier at P, from the towns.
This process is known as hyperbolic navigation.
These distances of point P from towns A and B is estimated by the soldier at point P, by measuring the delay localizes the receiver to a hyperbolic line on a chart.
Two hyperbolic lines will be drawn by taking timing measurements from the
towns A and B .
Point P will be at the intersection of the lines.
These distances of point P(The soldier's positions) from town A and town B were determined using the timing of the signals received from the two towns, due to the fact that point P was on a certain hyperbola.
The answer is
Final result :
x - 2
Step by step solution :
Step 1 :
1
Simplify —
3
Equation at the end of step 1 :
2 1
((—•x)-7)+((—•x)+5)
3 3
Step 2 :
Rewriting the whole as an Equivalent Fraction :
2.1 Adding a whole to a fraction
Rewrite the whole as a fraction using 3 as the denominator :
5 5 • 3
5 = — = —————
1 3
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
x + 5 • 3 x + 15
————————— = ——————
3 3
Equation at the end of step 2 :
2 (x + 15)
((— • x) - 7) + ————————
3 3
Step 3 :
2
Simplify —
3
Equation at the end of step 3 :
2 (x + 15)
((— • x) - 7) + ————————
3 3
Step 4 :
Rewriting the whole as an Equivalent Fraction :
4.1 Subtracting a whole from a fraction
Rewrite the whole as a fraction using 3 as the denominator :
7 7 • 3
7 = — = —————
1 3
Adding fractions that have a common denominator :
4.2 Adding up the two equivalent fractions
2x - (7 • 3) 2x - 21
———————————— = ———————
3 3
Equation at the end of step 4 :
(2x - 21) (x + 15)
————————— + ————————
3 3
Step 5 :
Adding fractions which have a common denominator :
5.1 Adding fractions which have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
(2x-21) + (x+15) 3x - 6
———————————————— = ——————
3 3
Step 6 :
Pulling out like terms :
6.1 Pull out like factors :
3x - 6 = 3 • (x - 2)
Final result :
x - 2
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Hope This Helps! :)
