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3 years ago

hello! i struggle with math A LOT so if u guys can help me with these questions with the work i would appreciate a lot

Mathematics

2 answers:

Scrat [10]3 years ago

7 0

Answer:

Exercise #1 = ³/₄

Exercise #3 = ¹/₂

Exercise #5 = 1 ¹/₉

Exercise #7 = ²/₅

Exercise #9 = ¹¹/₁₅

Step-by-step explanation:

When adding or subtracting fractions, you always have to find a common denominator first.

Exercise #1

⁵/₈ + ¹/₈

In this exercise, we already have the common denominator 8. Next, add the numerators together.

⁵/₈ + ¹/₈ = ⁶/₈

From here, we can simplify the fraction by dividing both the numerator and the denominator by 2.

6 ÷ 2 = 3

8 ÷ 2 = 4

This is as simplified our answer can get since there are no more common factors between the numerator (3) and the denominator (4).

⁶/₈ = ³/₄

Exercise #3

-¹/₄ + ³/₄

In this exercise, we already have the common denominator 4. Next, add the numerators together. (In this exercise, the numerators are -1 and 3. When adding a negative number, you can think of the equation as: 3 - 1 = 2)

-¹/₄ + ³/₄ = ²/₄

From here, we can simplify the fraction by dividing both the numerator and the denominator by 2.

2 ÷ 2 = 1

4 ÷ 2 = 2

This is as simplified our answer can get since there are no more common factors between the numerator (1) and the denominator (2).

²/₄ = ¹/₂

Exercise #5

⁵/₉ + ⁵/₉

In this exercise, we already have the common denominator 4. Next, add the numerators together.

⁵/₉ + ⁵/₉ = ¹⁰/₉

From here, we can simplify the fraction by turning it into a mixed number. To do this, we can subtract 9 from the numerator because 9 is the denominator and ⁹/₉ = 1. From this, we can determine that our simplified answer is:

¹⁰/₉ = 1 ¹/₉

Exercise #7

³/₁₀ + ¹/₁₀

In this exercise, we already have the common denominator 10. Next, add the numerators together.

³/₁₀ + ¹/₁₀ = ⁴/₁₀

From here, we can simplify the fraction by dividing both the numerator and the denominator by 2.

4 ÷ 2 = 2

10 ÷ 2 = 5

This is as simplified our answer can get since there are no more common factors between the numerator (2) and the denominator (5).

⁴/₁₀ = ²/₅

Exercise #9

⁷/₁₅ + ⁴/₁₅

In this exercise, we already have the common denominator 15. Next, add the numerators together.

⁷/₁₅ + ⁴/₁₅ = ¹¹/₁₅

This is as simplified our answer can get since there are no more common factors between the numerator (11) and the denominator (15).

~Hope this helps!~

elena-s [515]3 years ago

4 0

Pretty sure 1 is 6/8

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Which of the following rational numbers is equal to 4 point 5 with bar over 5?

steposvetlana [31]

41/9 = 4.5 with a bar over 5 because it is repeating

5 0

3 years ago

Read 2 more answers

13. In A ABC, if m BF is an angle bisector, find m

Tresset [83]

If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.

Given that m∠ABF=41° and BF is an angle bisector.

We are required to find the angle m∠BCE if BF is an angle bisector.

Angle bisector basically divides an angle into two parts.

If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.

In this way ∠ABC=2*∠ABF

∠ABC=2*41

=82°

In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.

∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)

∠BCE+90+82=180

∠BCE=180-172

∠BCE=8°

Hence if BF is an angle bisector then angle m∠BCE=8°.

Learn more about angles at brainly.com/question/25716982

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4 0

1 year ago

Tennis elbow is thought to be aggravated by the impact experienced when hitting the ball. The article "Forces on the Hand in the

Gnoma [55]

Answer:

Step-by-step explanation:

Hello!

The objective is to study whether there is a greater force after impacting on one- handed backhand drive in advanced tennis players than in intermediate tennis players.

Sample 1: Advanced tennis players

X₁: Force (N) on the hand just after impact on a one- handed backhand drive for an advanced tennis player.

n₁= 6

X[bar]₁= 40.29 N

S₁= 11.29

Sample 2: Intermediate players

X₂: Force (N) on the hand just after impact on a one- handed backhand drive for an intermediate tennis player.

n₂= 8

X[bar]₂= 21.40

S₂= 8.30

Assuming that both variables have a normal distribution and both population variances are equal, to compare these two populations is best to do so trough their population means using a t-test for independent samples.

If the force is greater for the advanced players than for the intermediate players, then you'd expect the population mean for the advanced players to be greater than the population mean for the intermediate players:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

α: 0.05

$t= \frac{(X_[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}$

$Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{5*127.51+7*68.92}{6+8-2} }= 9.66$

$t_{H_0}= \frac{(40.29-21.40)-0}{9.66\sqrt{\frac{1}{6} +\frac{1}{8} } } = 3.62$

Using the p-value approach, the decision rule is

If p-value ≤ α, reject the null hypothesis

If p-value > α, do not reject the null hypothesis

The p-value for this test is 0.00024, it is less than the level of significance, so the decision is to reject the null hypothesis.

This means that at a 5% significance level you can conclude that the average force experienced on the hand after a one-handed backhand drive for advanced players is greater than the average force experienced on the hand after a one-handed backhand drive for intermediate players.

I hope this helps!

3 0

3 years ago

One baseball team played 36 games throughout their entire season. If this baseball team won 18 of those games, then what percent

gizmo_the_mogwai [7]

They have won 50% of their games.

7 0

2 years ago

You have fit a regression model with two regressors to a data set that has 20 observations. The total sum of squares is 1000 and

Llana [10]

Answer:

Hence the adjusted R-squared value for this model is 0.7205.

Step-by-step explanation:

Given n= sample size=20

Total Sum of square (SST) =1000

Model sum of square(SSR) =750

Residual Sum of Square (SSE)=250

The value of R ^2 for this model is,

R^2 = \frac{SSR}{SST}

R^2 = 750/1000 =0.75

Adjusted $R^2$ :

$Adjusted R^2 =1- \frac{(1-R^2)\times(n-1)}{(n-k-1)}$

Where k= number of regressors in the model.

$Adjusted R^2 =1-(19\times 0.25/((20-2-1)) = 0.7205$

3 0

3 years ago