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Andreyy89
3 years ago
14

Find two numbers whose sum is 27 and product is 365​

Mathematics
2 answers:
yan [13]3 years ago
8 0
X^2 + (x-27)^2=365

(hopefully that was the answer you were looking for)
d1i1m1o1n [39]3 years ago
7 0

Answer:

There are no real number solutions to this.

Step-by-step explanation:

x + y = 27

xy = 365

y = 365/x

x + 365/x = 27

x^2 + 365 = 27x

x^2 - 27x + 365 = 0

x = [27 +/- sqrt(27^2 - 4 * 1 * 365)] / 2

x = (27 +/- sqrt (-731)/2

- No real roots.

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blsea [12.9K]

Answer:

It wouldn't.

Step-by-step explanation:

With the ratio, since Zeona has 36 cards, Kyle must have 54. If they each sold half, Kyle would have 27 and Zeona would have 18. So, the ratio would still be 3:2.

4 0
3 years ago
How do I solve this equation for x?
tester [92]
1) Divide both sides by 2
2x+12^2/3 =16

2) Solve the exponent
2x+12^2/3 =16

(2x+12^2/) ^3/2 =16^3/2 ( raise both sides to power)

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3) Subtract 12 from both sides
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4) divide both sides by 2
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Final answer : x = 26

7 0
3 years ago
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Step-by-step explanation:

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6 0
3 years ago
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IrinaK [193]

Answer:

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Step-by-step explanation:

We can find the zeros by factoring the equation using the zero product property.

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Step-by-step explanation:

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