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dimaraw [331]
3 years ago
9

The area of a square painting is 600 in.² to the nearest hundredth inch what is the perimeter of the painting?

Mathematics
1 answer:
Musya8 [376]3 years ago
6 0

\sqrt{600}  = 24.49
24.49*4

48.98

73.47

97.96

The perimeter of that square is 97.96.
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ivolga24 [154]

Answer

It is 11/12

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Step-by-step explanation:

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2 years ago
5 ( 3 squared x) + 9 ( 3 squared x)
yulyashka [42]

Answer:

42x^2

Step-by-step explanation:

5(3x^{2} )+9(3x^2)\\\\=(5+9)(3x^2)\\\\=14(3x^2)\\\\=42x^2

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In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir
Ede4ka [16]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}= p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

(a)

The sample selected is of size <em>n</em> = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204

So, the sampling distribution of sample proportion is \hat p\sim N(0.75,0.0204^{2}).

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

P(p-0.04

                                          =P(-1.96

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size <em>n</em> = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306

So, the sampling distribution of sample proportion is \hat p\sim N(0.75,0.0306^{2}).

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

P(p-0.04

                                          =P(-1.31

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

6 0
3 years ago
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guapka [62]

Answer:

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2 years ago
Read 2 more answers
Find mystery number
In-s [12.5K]

The number is less than 190,000 and greater than 180,000

5,000 more than the number has 187 thousands

2000 less than the number has 4 hundreds


180, 000 <n> 190, 000

180,000 + 2000 = n = 5000-187, 000

182,000 = n = 182, 000  

Or,  

 180, 000 <n> 190,000                    

 n + 5000= 187, 000                           n – 2000 = 180, 000

 n= 187, 000- 5000                             n = 180, 000 + 2000

 n= 182, 000                                       n= 182, 000

5 0
3 years ago
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