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3 years ago

Find the inverse function of y=1

Mathematics

2 answers:

weqwewe [10]3 years ago

7 0

Answer:F-^1(x)=-7x+7

Step-by-step explanation:To find the inverse, interchange the variables and solve for y.

AveGali [126]3 years ago

4 0

Answer:

To find the inverse, interchange the variables and solve for y

f^−1(x)=−7x+7

Hope I helped :)

You might be interested in

Determine which equation has exactly one real solution. PLS HELPP

sergey [27]

Answer:

b) $4x^2-12x+9=0$

Step-by-step explanation:

We can use the discriminant $b^2-4ac$ to determine how many real solutions a quadratic equation in the form $ax^2+bx+c=0$ has.

discriminant > 0 ⇒ 2 real solutions
discriminant = 0 ⇒ 1 real solution
discriminant < 0 ⇒ no real solutions

$5x^2+9x-4=0$

$b^2-4ac=9^2-4(5)(-4)=161 > 0\implies \textsf{2 solutions}$

$4x^2-12x+9=0$

$b^2-4ac=(-12)^2-4(4)(9)=0 \implies \textsf{1 solution}$

$-9x^2+6x+1=0$

$b^2-4ac=6^2-4(-9)(1)=72 > 0 \implies \textsf{2 solutions}$

$-2x^2-7=0$

$b^2-4ac=0^2-4(-2)(-7)=-56 < 0 \implies \textsf{no solutions}$

4 0

2 years ago

Maria is using a coordinate plane with the axes labeled only with integers. She says that the point (−0.5, 2) cannot be plotted

vodka [1.7K]

Answer:

Integers ={Positive Natuaral Number +Natural numbers having negative sign behind it+Zero}

={------,-3,-2,-1,0,1,2,3,..........}

→Points marked on the X and Y axis on the Coordinate Plane=Integers only

→Point to be marked on the coordinate plane =(-0.5,2)

→As, points on both X and Y axis are integers only.To mark, -0.5 , mark a line between , 0 and -1,that will be ,-0.5.

→You can mark , any terminating decimal on the number line, which is marked with integers only.

→Terminating decimals are those decimals having $2^a ,\text{or}5^b, \text{or} 2^a \times 5^b$ in the denominator of a fraction.

So, to plot any terminating Decimal on the coordinate plane, you have to use property of Rational Numbers ,which is, you can find infinite number of terminating Decimal between two terminating Decimal.

→Mark -0.5 between 0 and -1 on the X axis.Similarly, mark integer 2 on the Y axis.Draw a line parallel to Y axis ,passing from (-0.5,0) and line parallel to X axis passing through (0,2).The intersection of these two lines will be required point (-0.5,2).