2 years ago

Use logarithmic differentiation to find dy/dx

Mathematics

1 answer:

Agata [3.3K]2 years ago

3 0

Answer:

Hello,

Step-by-step explanation:

Let's say:

$y=x^{cotg(x)}\\\\ln(y)=cotg(x)*ln(x)\\\\\\\dfrac{y'}{y}=\dfrac{-1}{sin^2(x)} *ln(x)+\dfrac{cotg(x)}{x} \\\\\\y'=-\dfrac{x^{cotg(x)}*ln(x)}{sin^2(x)} +cotg(x)*x^{cotg(x)-1}\\$

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identify the amplitude and period of the function then graph the function and describe the graph of G as a transformation of the

mrs_skeptik [129]

Given the function:

$g(x)=cos4x$

Let's find the amplitude and period of the function.

Apply the general cosine function:

$f(x)=Acos(bx+c)+d$

Where A is the amplitude.

Comparing both functions, we have:

A = 1

b = 4

Hence, we have:

Amplitude, A = 1

To find the period, we have:

$\frac{2\pi}{b}=\frac{2\pi}{4}=\frac{\pi}{2}$

Therefore, the period is = π/2

The graph of the function is shown below:

The parent function of the given function is:

$f(x)=cosx$

Let's describe the transformation..

Apply the transformation rules for function.

We have:

The transformation that occured from f(x) = cosx to g(x) = cos4x using the rules of transformation can be said to be a horizontal compression.

ANSWER:

Amplitude = 1

Period = π/2

Transformation = horizontal compression.