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3 years ago

If you were to roll the dice one time what is the probability it will land on 3

Mathematics

1 answer:

Sonbull [250]3 years ago

8 0

Hey there!

The answer is 1/6. A dice has 6 numbers on it. 1-6. So it would be 1/6.

Hope this helped!

:))

You might be interested in

6. A factory has two types of machines.

Pie

210 pieces

Step-by-step explanation:

First, you need to figure out how many pieces a single machine can cut in a minute, so you need to divide 105 by 3, which gets you 35 pieces per minute.

Next, since we know there are 6 machines, and one machine canncut 35 pieces per minute, we can the figure out how many pieces all 6 cutting machines can cut in 1 minute. You would do this by making an equation such as this:

$35 \times 6 = x$

The x represents the total number of pieces cut by all 6 machines in one minute.

Next, since we now have an equation, we can go ahead and solve it. We would multiply 35 by 6, which would get us 210 pieces per minute that can be cut by all six machines

8 0

3 years ago

Read 2 more answers

How to add -89 and 17 step by step

Debora [2.8K]

Step-by-step explanation: The easiest way to do this and the way I commonly use is to subtract 17 from 89then make it negative as you are making the negative number smaller by adding a smaller number therefore your answer is -72

6 0

3 years ago

Oscar needs to purchase soft drinks for a staff party. He is

PilotLPTM [1.2K]

Answer:

sorry getting points

Step-by-step explanation:

4 0

3 years ago

The general form of an parabola is 2x2−12x−3y+12=0 .

Murljashka [212]

Answer:

The standard form of the parabola is $(x-3)^2=4*\frac{3}{8}(y+2)$

Step-by-step explanation:

The standard form of a parabola is

$(x-h)^2=4p(y-k)$ .

In order to convert $2x^2-12x-3y+12=0$ into the standard form, we first separate the variables:

$2x^2-12x+3y+12=0\\\\2x^2-12x+12=3y$

we now divided both sides by 2 to remove the coefficient from $2x^2$ and get:

$x^2-6x+6=\frac{3}{2}y$ .

We complete the square on the left side by adding 3 to both sides:

$x^2-6x+6+3=\frac{3}{2}y+3$

$x^2-6x+9=\frac{3}{2}y+3$

$(x-3)^2=\frac{3}{2}y+3$

now we bring the right side into the form $4p(y-k)$ by first multiplying the equation by $\frac{2}{3}$ :

$\frac{2}{3} *(x-3)^2=\frac{2}{3} *(\frac{3}{2}y+3)\\\\\frac{2}{3} *(x-3)^2=y+2$

and then we multiplying both sides by $\frac{3}{2}$ to get

$(x-3)^2=\frac{3}{2} (y+2)$ .

Here we see that

$4p=\frac{3}{2}$

$\therefore p=\frac{3}{8}$

Thus, finally we have the equation of the parabola in the standard form:

$\boxed{(x-3)^2=4*\frac{3}{8}(y+2)}$

5 0

3 years ago

How do you do this?PLZ HELP

Alisiya [41]

3(x^2+10x+5)-5(x-k)=
3x^2+30x+15-5x+5k=
3x^2+25x+15+5k

for this to be divisible by x every term must include x or get eliminated

the problematic terms are 15 and 5k
to eliminate them they must equal 0 when added:
15+5k=0
5k=-15
k=-3

so A) -3 is the solution

5 0

3 years ago