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3 years ago

If you were to roll the dice one time what is the probability it will land on 3

Mathematics

1 answer:

Sonbull [250]3 years ago

8 0

Hey there!

The answer is 1/6. A dice has 6 numbers on it. 1-6. So it would be 1/6.

Hope this helped!

:))

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If 30.s g of milk contains 18 C, how many

liubo4ka [24]

Answer:

the answer would be (244/30.5) x 18, so the answer should be 144!

Step-by-step explanation:

Put me the brainest. thanks

8 0

3 years ago

Read 2 more answers

All right guys help me out a little bit no jokes this is worth 13 points I need help with 432 / 73

Vesna [10]

Answer:

5.91780821918

Step-by-step explanation:

432/73 is the same as 432 ÷73=5.91780821918

Hope this helps ∞<3

7 0

3 years ago

The pipe fitting industry had 546.5 thousand jobs in 2015 and is expected to decline at an average rate of 3 thousand jobs per y

lesya692 [45]

Answer:

The amount of jobs from fitting industry shall decline in 5.5 percent from 2015 to 2025.

Step-by-step explanation:

Due to the assumption of a yearly average rate, a linear function model shall be used. The expected amount of jobs ( $n$ ) after a certain amount of years (t) is given by the following formula:

$n = n_{o} + \frac{\Delta n}{\Delta t}\cdot t$

Where:

$n_{o}$ - Initial amount of jobs in pipe fitting industry, measured in thousands.

$\frac{\Delta n}{\Delta t}$ - Average yearly rate, measured in thousands per year. (A decline is indicated by a negative sign)

If $n_{o} = 546.5$ , $t = 2025-2015 = 10\,years$ and $\frac{\Delta n}{\Delta t} = -3\,\frac{1}{years}$ , then:

$n = 546.5+\left(-3\,\frac{1}{year}\right)\cdot (10\,years)$

$n = 516.5$

The percent change in jobs from pipe fitting industry is calculated as follows:

$\%n = \left(1-\frac{n}{n_{o}}\right)\times 100\,\%$

$\% n = \left(1-\frac{516.5}{546.5}\right)\times 100\,\%$

$\%n = 5.5\,\%$

The amount of jobs from fitting industry shall decline in 5.5 percent from 2015 to 2025.

4 0

3 years ago

6. In a basketball game, Anton made 5 shots in 7 tries. What is the ratio of the

Dmitry [639]

Answer:

A 7:2

Step-by-step explanation:

6 0

3 years ago

Use the Quadratic Formula to solve x2 + 20x + 98 = 0

Lubov Fominskaja [6]

$ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\if\ \Delta \ \textless \ 0\ then\ no\ solution\\\\if\ \Delta =0\ then\ one\ solution\ x_0=\dfrac{-b}{2a}\\\\if\ \Delta \ \textgreater \ 0\ then\ two\ solutions\ x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\-----------------------------$

$x^2+20x+98=0\\a=1;\ b=20;\ c=98\\\\\Delta=20^2-4\cdot1\cdot98=400-392=8 \ \textgreater \ 0\\\sqrt\Delta=\sqrt8=\sqrt{4\cdot2}=\sqrt4\cdot\sqrt2=2\sqrt2\\\\x_1=\dfrac{-20-2\sqrt2}{2\cdot1}=\dfrac{-20-2\sqrt2}{2}=-10-\sqrt2\\\\x_2=\dfrac{-20+2\sqrt2}{2\cdot1}=\dfrac{-20+2\sqrt2}{2}=-10+\sqrt2$

3 0

3 years ago