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3 years ago

Mo-Qui has studied Spanish for half an hour longer than he studied History.

1 answer:

7 0

So,

Let s represent the time Mo-Qui spent studying Spanish and h represent the time Mo-Qui spent studying History.

s = h + 30
s > 2 hrs. 15 mins. (he isn't done yet)

Substitute
2 hrs. 15 mins. = h + 30 mins.

Subtract 30 mins. from both sides
1 hr. 45 mins. = h

However, s > 2 hrs. 15 mins., so h must be more than 1 hr. and 45 mins.

h > 1 hr. 45 mins.

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Question 2 <br><br> Find HY if YL = 9 .

damaskus [11]

Answer:

HY = 18

Step-by-step explanation:

The distance from the vertex to the centroid is twice the distance from the centroid to the midpoint , so

HY = 2 YL = 2 × 9 = 18

3 0

3 years ago

Given g(x)=-x-4g, solve for x when g(x)=9.

Jet001 [13]

Answer: i think it would be -2.5=x

Step-by-step explanation:

6 0

3 years ago

3 rhombi are connected at a point, side by side. All sides are congruent. Juan is making a model out of rhombi. Each rhombus wil

Wewaii [24]

Rhombus has all sides equal. The total amount of paper that will be needed to cover the wall is 396 in².

Given to us

Each rhombus will be 6 inches tall and 4 inches wide.

A.)

The area of each rhombus can be found using the formula,

$Area = \dfrac{1}{2} \times d_1 \times d_2$

We know that diagonals of the rhombus are of length 6 in and 4 in. therefore,

$Area = \dfrac{1}{2} \times 6 \times 4\\\\Area = 12\ in^2$

Hence, the area of the single rhombus is 12 in².

We know that the wall is 11 feet long, also, 1 foot = 12 inches, therefore,

11 feet = 132 in.

Now, since the wall is 132 in long and the width of the rhombus is 4 in, therefore, the number of rhombi that will be needed,

$\dfrac{132}{4} =33$

Hence, the number of rhombi that will be needed is 33.

We know the area of each paper rhombus, also, we know the number of rhombi that will be needed. Therefore,

$33 \times 12 = 396\ in^2$

Hence, the total amount of paper that will be needed to cover the wall is 396 in².

Learn more about Rhombus:

brainly.com/question/14462098

5 0

2 years ago

the perimeter of a rectangle is 62 meters. if the width were doubled and the length were increased by 21 meters, the perimeter w

iren [92.7K]

62=2w+2l
120= 2(2w)+ 2(l+21)

120=4w+2l+42
78= 4w+2l
39=2w+l
39-2w=l

Use substitution
62=2w+2(39-2w)
62= 2w+78-4w
62= -2w+78
-16=-2w
8=w

Plug w in
62=2(8)+2l
62=16+2l
46=2l
23=l

Final answer: Width=8, Length=23

6 0

3 years ago

What does changing the “a” do to the graph of a quadratic equation?

Marta_Voda [28]

Compresses or stretches it

4 0

3 years ago