Answer:
I = 0.002593 A = 2.593 mA
Explanation:
Current density = J = (3.00 × 10⁸)r² = Br²
B = (3.00 × 10⁸) (for ease of calculations)
The current through outer section is given by
I = ∫ J dA
The elemental Area for the wire,
dA = 2πr dr
I = ∫ Br² (2πr dr)
I = ∫ 2Bπ r³ dr
I = 2Bπ ∫ r³ dr
I = 2Bπ [r⁴/4] (evaluating this integral from r = 0.900R to r = R]
I = (Bπ/2) [R⁴ - (0.9R)⁴]
I = (Bπ/2) [R⁴ - 0.6561R⁴]
I = (Bπ/2) (0.3439R⁴)
I = (Bπ) (0.17195R⁴)
Recall B = (3.00 × 10⁸)
R = 2.00 mm = 0.002 m
I = (3.00 × 10⁸ × π) [0.17195 × (0.002⁴)]
I = 0.0025929449 A = 0.002593 A = 2.593 mA
Hope this Helps!!!
Answer:
55 kg
Explanation:
spring constant (k) = 600 N/m
mass of chair (Mc) = 12 kg
period of oscillation of chair and man (T) = 2.1 s
what is the mass of the astronaut (Ma) ?
mass of the astronaut (Ma) = total mass (Mt) - mass of chair (Mc)
where
- total mass (Mt) =
taking π as 3.142
total mass (Mt) =
total mass (Mt) = 67 kg
therefore
mass of astronaut = 67 - 12 = 55 kg
Answer:
Explanation:
Tension provides centripetal force in the circular motion . In circular motion work done by force = torque x angle
torque is zero as , centripetal force passes through axis of rotation that is center.
So work done by centripetal force = 0
So work done by tension on M = 0
C. distance
sometimes the equation can be:
w = F x D x cos(x)
where cos(x) is the angle between where the force is exerted and the object's displacement