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Ad libitum [116K]
4 years ago
14

compare the distance time graph for a fast-moving object with the distance time graph of a slower moving object

Physics
1 answer:
soldi70 [24.7K]4 years ago
8 0
The slope of the distance/time graph is the speed of the moving object. 
So the graph for a fast moving object will have a greater slope than the
graph for a slower moving object has.
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Why are light intensity, carbon dioxide concentration and temperature liimiting factors​
Harman [31]

Answer:

As carbon dioxide concentrations increase, so too does the rate of photosynthesis until a certain point where the graph levels off. At lower carbon dioxide concentrations carbon dioxide is the limiting factor because an increase in carbon dioxide causes an increase in photosynthesis.

Explanation:

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8 0
3 years ago
A jet with mass m = 90000.0 kg jet accelerates down the runway for takeoff at 1.6 m/s2.
leva [86]
This question requires the use of the equation of motion:
v = u + at [v is final velocity (0), u is initial velocity (24), a is acceleration, t is time (13)]
to calculate the acceleration. This can then be multiplied by the mass of the plane to obtain the net force via:
F = ma (F is force, m is mass, a is acceleration)
First, we calculate the acceleration:
0 = 24 + 13(a)
a = -24/13 m/s^2
The force is then:
F = 90000 * (-24/13)
F = -1.66*10^5 Newtons
The negative sign indicates that the force and acceleration are in the opposite direction as the velocity (since we took velocity to be positive)
6 0
4 years ago
One hazard of space travel is debris left by previous missions. There are several thousand objects orbiting Earth that are large
Citrus2011 [14]

Answer:

The correct answer is "6666.67 N".

Explanation:

The given values are:

Mass,

m = 0.100

Relative speed,

v = 4.00 x 10³

time,

t = 6.00 x 10⁻⁸

As we know,

⇒  F=m(\frac{\Delta v}{\Delta t} )

On substituting the given values, we get

⇒      =0.100\times 10^{-6}(\frac{4\times 10^3}{6\times 10^{-8}} )

⇒      =6666.67 \ N

7 0
3 years ago
Two objects, one with a mass of and the other with a force of 30.0kg experience a gravitational force of attraction of 7.50 * 10
nydimaria [60]

Answer:

Explanation:

The formula for this is

F_g=\frac{Gm_1m_2}{r^2} where F is the gravitational force, G is the gravitational constant, m1 is the mass of one object and m2 is the mass of the other object. We are looking for r, the distance between the centers of their masses.

Filling in:

7.5*10^{-8}=\frac{6.67*10^{-11}(90.0)(30.0)}{r^2} and moving things around to solve for r:

r=\sqrt{\frac{6.67*10^{-11}(90.0)(30.0)}{7.5*10^{-8}} } Doing all that and rounding to the 3 sig fig's you need gives us a distance of 1.55 m

8 0
3 years ago
3. Imagine a 10kg block moving with a speed of 20m/s<br> calculate the kinetic energy of this block
MatroZZZ [7]
The formula of the kinetic energy is:
E_{k}  =  \frac{m v^{2} }{2}
where m is a mass of the object, v is speed of the object at the moment of time. So we have:
E_{k}  =  \frac{10* 20^{2} }{2}  = 2000J
The answer is 2000 Joules.
6 0
3 years ago
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