Answer:
-4.37 * 10^(-18) J
Explanation:
Parameters given:
Charge of a proton, Qp = 1.6022 * 10^(-19) C
Charge of an electron, Qe = -1.6022 * 10^(-19) C
Distance between proton and electron, d = 0.529 × 10^(−10) m
The amount of work done is given as:
W = F * d
Where F = electrostatic force
d = distance between them
Electrostatic force is given as:
F = (k * Qp * Qe) / d²
F = (9 * 10^9 * 1.6022 * 10^(-19) * -1.6022 * 10^(-19)) / (0.529 × 10^(−10))²
F = -8.26 * 10^(-8) N
Work done will be:
W = -8.26 * 10^(-8) * 0.529 × 10^(−10)
W = -4.37 * 10^(-18) J
Answer:
option A
Explanation:
given,
light is incident on the plane surface at (i) = 55°
angle of refraction (r) = 37°
μ is the refractive index of the material
using Snell's law
The refractive index of the material is
hence, the correct answer is option A
<span>To answer this question, the equation that we will be using is:
y = A cos bx + c
where A = amplitude, b = 2 pi/Period, Period = 12 hrs, c = midline,
x = t and y = f(t)
A = 1/2 (Xmax - Xmin)
12 - 2 / 2 = 10/2 = 5
b = 2 pi / 12 = pi/6
c = 1/2 (Xmax + Xmin)
12+2/2 = 7
answer: f(t) = 5 cos pi/6 t + 7 </span>
Answer:
Part a)
When rotated about the mid point
Part b)
When rotated about its one end
Explanation:
As we know that the angular acceleration of the rod is rate of change in angular speed
so we will have
Part a)
When rotated about the mid point
now torque is given as
Part b)
When rotated about its one end
now torque is given as