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3 years ago

13

At Coney Island, it costs $5.75 to enter the amusement park, cotton candy costs $3.20, and each ride costs $4.45. Maria wants to

go to the park, buy some cotton candy p, and ride some rides. If she had $25, but needs to spend $2.25 on a metrocard to get to the park, and $2.25 to get back home, who many rides will she be able to ride? Plz I will give you 100 points

2 answers:

BigorU [14]3 years ago

8 0

She will be able to go on about 5

rides at least

Art [367]3 years ago

3 0

First, let’s subtract $4.50 ($2.25 + $2.25) from $25

$25 - $4.50 = $20.50

Now we know she has $20.50 to spend at the amusement park.

Let’s divide $20.50 by $4.45 (the price each ride costs), but first, we’ll round down to make it easier to divide

$20.50 = $20

$4.45 = $4

$20 ÷ $4 = 5

Therefore, Maria will be able to ride <u>about</u> 5 rides

Hope this helps you

Brainliest would be appreciated

-AaronWiseIsBae

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3 years ago

The area of parallelogram WXYZ is approximately 45 square units.

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Answer:

Option (4)

Step-by-step explanation:

Area of a triangle = $\frac{1}{2} (a.b.\text{Sin}\theta)$

Where a and b are the sides of a triangle and θ is the angle between the sides a and b.

By this rule,

Area of ΔWZY = $\frac{1}{2}(\text{WZ}).(\text{YZ}).\text{Sin}(115)$

45 = $\frac{1}{2}(\text{YZ}).(10).\text{Sin}(115)$

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3 years ago

A city police officer using radar checked the speed of 26 cars as they were travelling down a city street and the data is given

pychu [463]

Answer: The distribution of the data set is positively skewed.

<u>Explanation: </u>

In order to see whether the given data set is symmetric, positively skewed or negatively skewed, we will find the mean, median and mode of the given data set.

For symmetric distribution, $Mean = Median=Mode$

For positively skewed distribution, $Mean > Median>Mode$

For negatively skewed distribution, $Mean < Median$

The mean of the given data set is given below:

$Mean = \frac{27+23+22+38+43+24+25+23+22+54+31+30+29+48+27+25+29+28+26+33+25+21+23+34+20+23}{26}$

$=\frac{753}{26}$

$=28.96$

Now, the Median is:

To find the median we need to sort the data in ascending order as:

$20,21,22,22,23,23,23,23,24,25,25,25,26,27,27,28,29,29,30,31,33,34,38,43,48,54$

$Median=\left(\frac{N+1}{2} \right)^{th} item$

$=\left(\frac{26+1}{2}\right)^{th} item$

$=13.5^{th} item$

$=26+0.5 \times (27-26)$

$=26.5$

$\therefore Median = 26.5$

The mode is the most frequently occurring observation. Therefore the mode is:

$Mode=23$

Since the $Mean >Median>Mode$ , therefore the distribution of the given data set is positively skewed.

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4 years ago

A farmer is tracking the amount of corn his land is yielding each year. He finds that the function f(x) = −x2 + 20x + 50 models

polet [3.4K]

Answer:

The crop yield increased by 9 pounds per acre from year 1 to year 10.

Step-by-step explanation:

To solve this we are using the average rate of change formula: $Av=\frac{f(x_2)-f(x_1)}{x_2-x_1}$ , where:

$x_2$ is the second point in the function

$x_1$ is the first point in the function

$f(x_2)$ is the function evaluated at the second point

$f(x_1)$ is the function evaluated at the first point

We know that the first point is 1 year and the second point is 10 years, so $x_1=1$ and $x_2=10$ . Replacing values:

$Av=\frac{-(10)^2+20(10)+50-[-(1)^2+20(1)+50]}{10-1}$

$Av=\frac{-100+200+50-[-1+20+50]}{9}$

$Av=\frac{150-[69]}{9}$

$Av=\frac{150-69}{9}$

$Av=\frac{81}{9}$

$Av=9$

Since $f(x)$ represents the number of pounds per acre and $x$ the number of years, we can conclude that the crop yield increased by 9 pounds per acre from year 1 to year 10.

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4 years ago