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Zinaida [17]
3 years ago
11

–2x(–3x 2 y)(2y) = ? A. 12x 3y 2 B. –3xy2 C. 3xy2 D. –12x 3y 2

Mathematics
1 answer:
Rina8888 [55]3 years ago
3 0

Answer:

Option A - -2x(-3x^2y)(2y)=12x^3y^2

Step-by-step explanation:

Given : Expression -2x(-3x^2y)(2y)

To find : Solve the expression ?

Solution :

Step 1 - Write the expression

-2x(-3x^2y)(2y)

Step 2 - Multiply the first two bracket in multiplication if base are same power get added and apply symbol rule of multiplication (-)(-)=(+)

=(6x^3y)(2y)

Step 3 - Again multiply the bracket,

=12x^3y^2

Therefore, Option A is correct -2x(-3x^2y)(2y)=12x^3y^2

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Read 2 more answers
A) Find a number $0\leq x<14$ that solves the congruence $9x \equiv 9 \pmod{14}$.
Rus_ich [418]
 

A) Find a number 0\leq x that solves the congruence 9x \equiv 9 \pmod{14}<span>.

</span>9x \equiv 9 \pmod{14} means that 9x-9 is a multiple of 14, 
<span>
that is 9(x-1) is a multiple of 14. A clear solution in the set is x=1



b) Find a number </span>0\leq x that solves the congruence 3x \equiv 4 \pmod{5}<span>.


</span>3x \equiv 4 \pmod{5} means that 3x-4 is a multiple of 5, 
<span>
x</span>∈{0, 1, 2, 3, 4} , so for these values 3x-4 becomes {-4, -1, 2, 5, 8}.

so x= 3 <span>


c)Find a number </span>0\leq x that solves the congruence 999x \equiv 998 \pmod{1000}<span>.


</span>999x \equiv 998 \pmod{1000} means that 999x-998 is a multiple of 1,000<span>

we can check that for x=2,         999*2-998=1,998-998=1,000


d)Find a number </span>0\leq x that solves the congruence 4x \equiv 17 \pmod{21}

4x \equiv 17 \pmod{21} means that 4x-17 is a multiple of 21, 

fro x=7, 4x=28 and so 4x-17=28-17=21 is a multiple of 21.



Answers:

A) 1
B) 3
C) 2
D) 4
6 0
3 years ago
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