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3 years ago

What are the answers here? ;)

Mathematics

1 answer:

Vesna [10]3 years ago

5 0

Answer:

Function B has a greater rate of change.

Function B has a greater y-intercept.

Step-by-step explanation:

Rate of change: rise ÷ run

Function A: (9-5)÷(3-1) = 2

Function B: 3 (based on equation)

Function A: 5-2 = 3

Function B: 4 (based on equation)

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Simplfy the expression: (x - 9)^2

deff fn [24]

The answer would be x^2-18x+81. This can be found be writing "(x-9)^2" twice, and distributing. Combine like terms, and you should get this answer.

6 0

3 years ago

The library has DVDs on crime, adventure and science fiction.

kozerog [31]

Answer:

The library has 1,056 crime DVDs.

Step-by-step explanatiion:

Crime : Adventure : Science

11x : 6x : 10x

6x+384=10x

384=4x

x=96

The number of crime DVDs is 11x.

We found that x=96.

So, the number of crime DVDs the library has is equal to 11*96.

11*96=1,056.

Hope this helps!

6 0

3 years ago

Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n

aliya0001 [1]

Answer:

$f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}$

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

$f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...$

We first compute the n-th derivative of $f(x)=\ln(1+2x)$ , note that

$f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\$

Now, if we compute the n-th derivative at 0 we get

$f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!$

and so the Maclaurin series for f(x)=ln(1+2x) is given by

$f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2 \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}$

3 0

3 years ago

A certain company changes for teling a rectangular room include the cost of the material used and a flat rate of instalitation.T

nika2105 [10]

Answer:

nknknStep-by-step explanation:

5 0

3 years ago

A ship traveled 120 km with the current, and then turned around and traveled back, spending 5h and 24 min on its trip. Find the

nadya68 [22]

Yah same im also an RSM student. 8th Honors?

7 0

3 years ago