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djverab [1.8K]
3 years ago
9

What can I do with a coordinations and the slope

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
7 0

You can plot a linear equation, if you are given the coordinates and the slope for THE SAME line.

Assuming you have those, the first step is to find the y-intercept.

That is done by replacing x and y in the general formula by their coordinated counterparts, and replacing m by the slope that is given to you.

Let's assume the coordinates you are given are (5,10), and the slope you are given is 1.

By substituting into the general formula...

y=mx+c\\(10)=(1)(5)+c\\10=5+c\\10-5=c\\c=5

...we can see that it is possible to find the y-intercept (c).

Knowing the y-intercept, it is possible to plot the line and solve any question.

I'll leave a picture of the example used above when graphed.

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3 years ago
The Rogers Park cafeteria sells veggie pizza and cheese pizza. Today they sold 25 pizzas at lunch. They sold seven more cheese p
MA_775_DIABLO [31]
Let the number sold of veggie pizza be a
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3 years ago
Which expression is equivalent to...? Screenshots attached. Please help! Thank you.
Studentka2010 [4]

Answer:

4x^{3} y^{2} (\sqrt[3]{4 x y})

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }

Then we'll extract the 4 from the cubic root.  We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}

The answer is then:

4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})

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Step-by-step explanation:

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zhenek [66]

<em>Greetings from Brasil...</em>

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