Answer:
The total resistance in a parallel circuit is always less than any of the branch resistances. Adding more parallel resistances to the paths causes the total resistance in the circuit to decrease. As you add more and more branches to the circuit the total current will increase because Ohm's Law states that the lower the resistance, the higher the current.
Explanation:
The electrostatic force between the two ions is
Explanation:
The electrostatic force between two charged particle is given by Coulomb's law:
where
is the Coulomb's constant
are the two charges
r is the separation between the two charges
In this problem, the ion of sodium has a charge of
while the ion of chlorine has a charge of
And the distance between the two ions is
Substituting, we find the electrostatic force between the two ions:
where the negative sign simply means that the force is attractive, since the two ions have opposite charge.
Learn more about electrostatic force:
brainly.com/question/8960054
brainly.com/question/4273177
#LearnwithBrainly
Answer:
Current in circuit = 2 amp
Explanation:
Given:
Voltage of battery = 10 V
First Resistance R1 = 1 ohm
Second Resistance R2 = 4 ohm
Resistor connected in series
Find:
Current in circuit
Computation;
Resistor connected in series
So,
Total resistance R = First Resistance R1 + Second Resistance R2
Total resistance R = 1 ohm + 4 ohm
Total resistance R = 5 ohm
Current in circuit = V / R
Current in circuit = 10 / 5
Current in circuit = 2 amp
The angle of incidence, when there is perfect transmission is the polarization angle. The expression for the polarization is
Where
= Polarization angle
= Angle with the vertical axis
We have that the angle is
The ratio of the intensities depends on the cosine of the polarization angle. The polarization angle found from the wearer’s leaning angle can be used to find the fraction of the reflected ray intensity that will pass through the sunglasses.
Applying the Malus Law we have that
Here,
= Final intensity
= Initial intensity
Replacing we have,
Therefore the fraction of the reflected light intensity which passes through the sunglasses is 0.11