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Anit [1.1K]
3 years ago
6

8. In explosives, potential energy is generally

Physics
1 answer:
anastassius [24]3 years ago
4 0

Answer:

In explosives,potential energy is in the stored form of chemical energy.

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A block and tackle is used to lift an automobile engine that weighs 1800 N. The person exerts a force of 300 N to lift the engin
Sidana [21]

Answer:

1800/300 = 6ropes

Explanation:

The engine weighs 1800N and the person exerts a force of 300N, so for him to lift the engine and exerting a force of 300N all through we divide the weight of the engine by the force exerted to know how many ropes are used. Which makes it 6 thereby each rope uses 300N to lift the engine.

8 0
3 years ago
You are given an unknown solid substance of mass 500 g and you want to estimate its specific heat. unfortunately, you don’t have
Julli [10]

Answer:

Option C) 2,090 J/(mol K)

Explanation:

Data:

Volume in the beaker = 429 ml

temperature  = 20° C

Density = 789 kg/m³

Equilibrium reading = 429

volume change = 29 ml

                          = 0.029 L

Energy change = mcΔT

                       U + PΔV

7 0
3 years ago
Name three categories that are used to classify the elements in the periodic table?
nikitadnepr [17]

Answer:

metals,nonmetals, and inert gases

Explanation:

6 0
3 years ago
Read 2 more answers
Some elements are highly unstable and break apart within seconds, making them difficult to study. How can the periodic table hel
rusak2 [61]
You can look at groups in the same group (the columns), since they tend to have similar properties. For example, the alkali metals in group one react aggressively with water and form white compounds.
8 0
3 years ago
Read 2 more answers
A proton moves with a speed of 1.00 x 106 m/s perpendicular to a magnetic field, B. As a result, the proton moves in circle of r
Softa [21]

Answer:

0.0109 m ≈ 10.9 mm

Explanation:

proton speed = 1 * 10^6 m/s

radius in which the proton moves = 20 m

<u>determine the radius of the circle in which an electron would move </u>

we will apply the formula for calculating the centripetal force for both proton and electron ( Lorentz force formula)

For proton :

Mp*V^2 / rp  = qp *VB   ∴  rp = Mp*V / qP*B    ---------- ( 1 )

For electron:

re = Me*V/ qE * B -------- ( 2 )

Next: take the ratio of equations 1 and 2

re / rp = Me / Mp                                 ( note: qE = qP = 1.6 * 10^-19 C )

∴ re ( radius of the electron orbit )

= ( Me / Mp ) rp

= ( 9.1 * 10^-31 / 1.67 * 10^-27 ) 20

= ( 5.45 * 10^-4 ) * 20

= 0.0109 m ≈ 10.9 mm

5 0
3 years ago
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