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kipiarov [429]
3 years ago
10

Two cyclists leave a city at the same time, one going east and the other going west. The westbound cyclist bikes at 3 mph faster

than the eastbound cyclist. If after 6 hours they are 162 miles apart, how fast is each cyclist riding?
If you can solve this, can you please show your work and explain what I need to plug in where, and what equation I need to use? This is so confusing.
Mathematics
1 answer:
NikAS [45]3 years ago
7 0
We will say that the eastbound cyclist is going x mph. This means that the westbound cyclist is going x+3 mph.
They are both cycling for 6 hours and end up 162 miles apart.
Distance=rate*time
6x+6(x+3)=162
6x+6x+18+162
12x=144
x=12
So, the eastbound cyclist is going 12 mph.
Remember the westbound cyclist is going 3 mph faster, so s/he is going 15 mph.
Hope this helps!!
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