What equation is solved by the graphed systems of equations? Two linear equations that intersect at the point negative 1, negati
1 answer:
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Answer: The number of different combinations of 2 vegetables are possible = 15 .
Step-by-step explanation:
In Mathematics , the number of combinations of selecting r values out of n values =
Given : Number of available vegetables = 6
Then, the number of different combinations of 2 vegetables are possible will be :
Hence , the number of different combinations of 2 vegetables are possible = 15 .
Answer:
Step-by-step explanation:
Let's find the answer.
Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.
Equations:
Eq. 1 : x1 + 2x2 + 5x3 = 5
Eq. 2 : x1 + x2 + x3 = 6
E1. 3 : 4x1 + 6x2 + 5x3 = 7
Coefficients for x1 ; x2 ; x3
From eq. 1 : 1 ; 2 ; 5
From eq. 2 : 1 ; 1 ; 1
From eq. 3 : 4 ; 6 ; 5
So matrix A is:
And the vector of vriables (X) is:
Now we can find the resulting vector (B) using the 'resulting values' from each equation:
In conclusion, AX=B is: