Answer: 49.85%
Step-by-step explanation:
Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.
i.e.
and 
To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.
i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and
.
i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between
and
. (1)
According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.
i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.
i.e.,The approximate percentage of lightbulb replacement requests numbering between
and
= 49.85%
⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%
Answer:
B
I hope this could help you ^^
5.95 + 2.95 = 8.9
8.9 + 29.95 = 38.85
62.35 - 38.85 = 23.5
So Daniel spent $23.50 on long distance calling
Here's what i found online:
<span>a/3+4=6
We simplify the equation to the form, which is simple to understand
<span>a/3+4=6
Simplifying:
<span> + 0.333333333333a+4=6
We move all terms containing a to the left and all other terms to the right.
<span> + 0.333333333333a=+6-4
We simplify left and right side of the equation.
<span> + 0.333333333333a=+2
We divide both sides of the equation by 0.333333333333 to get a.
<span>a=6
Hope this helped :-)</span></span></span></span></span></span>