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spayn [35]
4 years ago
5

Let the graph of f(x) represent the cost in thousands of dollars to feed the zoo animals daily, where x is the number of animals

measured in hundreds. What does the solution to the function (2, 8) represent?
a graph of a function that increases from the lower left, travels through an ordered pair labelled, 2, 8, and then increases toward the right

There are 800 animals, and the cost is $2,000 daily.
There are 8,000 animals, and the cost is $200 daily.
There are 200 animals, and the cost is $8,000 daily.
There are 2,000 animals, and the cost is $800 daily.
Mathematics
2 answers:
Snowcat [4.5K]4 years ago
6 0

Answer: (C). There are 200 animals, and the cost is $8,000 daily.

Step-by-step explanation: We already know (x) is the number of animals measured in hundreds and it would go on the x axis. And that would mean that (f) is going to be on the y axis. Go over on the x axis 2 then for the y axis go up 8 on the y axis and you would get (2,8)= (200 animals, $8,000 a day)

vichka [17]4 years ago
5 0

There are 200 animals, and the cost is $8,000 daily

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The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100
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Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of 660, hence \mu = 660.
  • The standard deviation is of 90, hence \sigma = 90.
  • A sample of 100 is taken, hence n = 100, s = \frac{90}{\sqrt{100}} = 9.

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{670 - 660}{9}

Z = 1.11

Z = 1.11 has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

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