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TiliK225 [7]
2 years ago
7

i think of a number. if i divide the sum of 5 and the number by 3, the result is 2 less than one quarter of the number. find the

number
Mathematics
1 answer:
Marrrta [24]2 years ago
7 0

Answer:

x = 4.75

Step-by-step explanation:

<u>(5 +X</u><u> )/3</u>  = 2 - <u> X/4</u>

<h3>   <u>(5 +X</u><u> )/3</u>  = 8 - X  </h3><h3>5+ X = 3 (8 - X)   </h3><h3>  5+ X = 24 - 3X transposing terms</h3><h3>X+ 3X= 24 -5</h3><h3>   4X = 19</h3><h3>      X = 19/4 </h3><h3>X = 4.75</h3>
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Kaylis [27]

Answer:

Option B) {(1, -1), (-3, -3), (2, 4)}

Step-by-step explanation:

<u><em>The correct inequality is </em></u>

y>\frac{1}{2}x-2

The solution of the inequality is the shaded area above the dashed line y=\frac{1}{2}x-2

see the attached figure to better understand the problem

we know that

If a ordered pair satisfy the inequality, then the ordered pair must lie in the shaded area of the solution

<u><em>Verify each case</em></u>

case A) {(6, 1), (-1, -3), (4, 4)}

ordered pair (6,1)

For x=6, y=1

substitute in the inequality

1>\frac{1}{2}(6)-2

1>1 ---> is not true

therefore

The point not satisfy the inequality

case B)  {(1, -1), (-3, -3), (2, 4)}

ordered pair (1,-1)

For x=1, y=-1

substitute in the inequality

-1>\frac{1}{2}(1)-2

-1>-1.5 ---> is true

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The point satisfy the inequality

ordered pair (-3,3)

For x=-3, y=3

substitute in the inequality

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3>-3.5 ---> is true

so

The point satisfy the inequality

ordered pair (2,4)

For x=2, y=4

substitute in the inequality

4>\frac{1}{2}(2)-2

4>-1 ---> is true

so

The point satisfy the inequality

therefore

The set contains only points that satisfy the inequality

case C) {(1, -1), (-3, -3), (4, -2)}

ordered pair (4,-2)

For x=4, y=-2

substitute in the inequality

-2>\frac{1}{2}(4)-2

-2>0 ---> is not true

therefore

The point not satisfy the inequality

case D) {(-1, -3), (-3, -3), (2, 4)}

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For x=-1, y=-3

substitute in the inequality

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3 years ago
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Answer:

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\begin{gathered}\end{gathered}

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\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{Using Formula:}}}}}}}\end{gathered}

{\dag{\underline{\boxed{\sf{Amount  ={P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}}}

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\quad {:\implies{\sf{Amount  = \bf{4000{\bigg(1  +  \dfrac{6}{100}{\bigg)}^{3}}}}}}

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\quad{: \implies{\sf{Compound \: Interest = \bf{4764.064- 4000 }}}}

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