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Allisa [31]
3 years ago
7

Calculate (4.369 x 10^5)+(2.6 x 10^3) Write your answer in scientific notation.

Mathematics
1 answer:
Verizon [17]3 years ago
3 0

4.369x^10^5+2.6x^10^3

Simplifies to:

Let's simplify step-by-step.

4.369x^100000+2.6x^1000

There are no like terms.

Answer:

=4.369x^100000+2.6x^1000

Step-by-step explanation:

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a teacher promised a movie day to the class that did better, on average, on their test. The box plot shows the results of the te
natka813 [3]

The question is incomplete. The complete question is

A teacher promised a movie day to the class that did better, on average, on their test. The box plot shown in the below-mentioned figure shows the results of the test.

Which class should get the reward, and why?

- The 2nd-period class should get the reward. They have the highest score, a perfect 100.

- The 2nd-period class should get the reward. They have a higher median.

- The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

- The 4th-period class should get the reward. Their lowest score is an outlier and should be thrown out.

The box plot shown in the question provides the information that
In 2nd period the minimum of the data is 77, first quartile is 78, median of the data is 89, third quartile is 92 and the maximum of the data is 100.
Hence, the mean of the results of 2nd period is

\frac{77+78+89+92+100}{5}=87.2

In 2nd period the minimum of the data is 72, first quartile is 83, median of the data is 89, third quartile is 96 and the maximum of the data is 98.

Hence, the mean of the results of the 4th period is

\frac{72+83+89+96+98}{5}=87.6

Hence, obviously, the 4th period is having more mean.

Moreover, we can observe that if more of the marks are on the higher side the average will automatically be more. Hence, as the first and the third quartiles are more on the 4th-period, so the average marks for the 4th period must be better.

So, just by observing the box plot, we can give the statement that  "The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class. "

Therefore, the 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

Learn more about box plots here-

brainly.com/question/1523909

#SPJ10

6 0
2 years ago
Algebra need help ASAP !!!
kirza4 [7]
The top one on the left is equivalent to the second one down on the right; the second one down on the left is equivalent to the bottom one on the right; the third one down on the left is equivalent to the second one down on the right, and the last one on the left is the only one remaining on the right.
7 0
3 years ago
Is the product of 10 over 3 bigger than 54
Stels [109]

Answer:

no

Step-by-step explanation:

If you are talking 10 to the power of three then 54 is bigger. (:

6 0
4 years ago
.6(2k - 3) = 3(4k + 5)<br> Hellppp pleaseee
muminat

Answer:

Step-by-step explanation:

.6(2k-3)=3(4k+5) foil

1.2K-1.8=12k+15 subtract 1.5k from both sides

-1.8=10.8k+15 subtract 15 from both sides

-16.8=10.8k divide by 10.8

k= -1.5

7 0
3 years ago
Tomas makes balloon sculptures at a circus.In 90 minutes he makes 150 balloons to make 30 identical balloon sculptures how many
maxonik [38]
The answer to your question is 3.
6 0
3 years ago
Read 2 more answers
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