3 years ago

Jim Has a monthly

Mathematics

1 answer:

Anestetic [448]3 years ago

8 0

Answer is d hope this helps have a great day and you have

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Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma

Lubov Fominskaja [6]

Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with $\mu = 112$ inches and $\sigma = 14$ inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - $\mu = 112$ inches

Standard deviation - $\sigma = 14$ inches

The z-score formula is given by, $Z=\frac{x-\mu}{\sigma}$

Now,

$P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})$

$P(X>140)=P(Z>\frac{140-112}{14})$

$P(X>140)=P(Z>\frac{28}{14})$

$P(X>140)=P(Z>2)$

$P(X>140)=1-P(Z$

The Z-score value we get is from the Z-table,

$P(X>140)=1-0.9772$

$P(X>140)=0.0228$

Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

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How much is 1.4 kg minus 650 grams

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First of all you have to convert kg to grams

so there is 1 kg in 1000g
.4 kg is 400g
1000+400= 1400g

1400-650 = 750 kg

that's your final answer

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When graphed, which parabola opens downward? y = –3x2 y = (x – 3)2 y = x2 – 3

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The answer to this question is y = –3x^2, just had this on e2020 :)

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