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Marrrta [24]
3 years ago
13

Mhanifa please help! Solve each proportion. Round your answer to the nearest hundreth

Mathematics
1 answer:
Marianna [84]3 years ago
4 0

Answer:

  • 5) m/5 = 7/2 ⇒ m = 5*7/2 ⇒ m = 35/2
  • 6) 7/4 = r/5 ⇒ r = 5*7/4 ⇒ r = 35/4
  • 7) 7/6 = 5/x ⇒ x = 5*6/7 ⇒ x = 30/7
  • 8) 6/5 = 2/(5n) ⇒ 5n*6 = 5*2 ⇒ n = 10/30 ⇒ n = 1/3
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the angle of depression from an airplane at an altitude of 8000 feet to the airport is 7 degrees. Find the direct distance from
Aleks [24]

Answer:

direct distance = 65,644.07 feet

horizontal distance = 65,154.77 feet

Step-by-step explanation:

The angle of depression is the angle that the airplane does with the horizontal plane.

So, if this angle is 7° and the airplane is at an altitude if 8000 feet, we can find the direct distance and the horizontal distance using the tangent and the sine relations of the angle.

In the tangent of the angle, the opposite side will be the height of the airplane, and the adjacent side will be the horizontal distance (hd), so:

tangent(7) = 8000 / hd

hd = 8000 / tangent(7) = 65,154.77 feet

In the sine of the angle, the opposite side will be the height of the airplane, and the hypotenusa will be the direct distance (d), so:

sine(7) = 8000 / d

d = 8000 / sine(7) = 65,644.07 feet

5 0
3 years ago
Find the surface area of the composite figure.
kakasveta [241]

Answer:

508.68 in^2

Step-by-step explanation:

The equation given: 2πr^2+2πrh

Givens: r = 3 in, h = 3*8 in = 24 in, π ≈ 3.14

Substitution: 2(3.14)3^2+2(3.14)3*24

Solution: 508.68

7 0
3 years ago
If a fair penny is tossed 24 times and comes up heads 18 times, what is the probability of heads coming up on the 25th flip of t
Allushta [10]
There’s a 75% chance. i’m not sure if that the answer ur looking for but i divided 24 by 18 and got 0.75
8 0
3 years ago
70. Suppose that you currently have one credit card with a balance of $10,000 at an annual rate of 24.00% interest. You have sto
Simora [160]

Answer:

1+r+r^{2}+r^{3}+.....+r^{n-1} = \frac{1-r^{n}}{1-r}

Step-by-step explanation:

Taking the succession:

1+r+r^{2}+r^{3}+.....+r^{n-1}

You can multiply and divide by 1-r without chaging the result:

\frac{1-r}{1-r} (1+r+r^{2}+r^{3}+.....+r^{n-1})

Distributing the upper part of the fraction you have:

\frac{1}{1-r} (1-r+r-r^{2}+r^{2}-r^{3}+r^{3}-r^{4}+.....+r^{n-1}-r^{n})

As can be seen all the intermediate members will be canceled by a same member with opposite sign, only (1-r^{n}) will be left so:

1+r+r^{2}+r^{3}+.....+r^{n-1} = \frac{1-r^{n}}{1-r}

5 0
3 years ago
A courier service company wishes to estimate the proportion of people in various states that will use its services. Suppose the
Orlov [11]

Answer:

95.44% probability that the sample proportion will differ from the population proportion by less than 0.03.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question:

p = 0.05, n = 212, \mu = 0.05, s = \sqrt{\frac{0.05*0.95}{212}} = 0.015

What is the probability that the sample proportion will differ from the population proportion by less than 0.03?

This is the pvalue of Z when X = 0.03 + 0.05 = 0.08 subtracted by the pvalue of Z when X = 0.05 - 0.03 = 0.02. So

X = 0.08

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.08 - 0.05}{0.015}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 0.02

Z = \frac{X - \mu}{s}

Z = \frac{0.02 - 0.05}{0.015}

Z = -2

Z = -2 has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

95.44% probability that the sample proportion will differ from the population proportion by less than 0.03.

6 0
3 years ago
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