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bazaltina [42]
3 years ago
7

Write 2.1111111 as a mixed number

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
7 0
.11111... = 1/9
2.0 = 2
2 1/9 is your answer
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Ray Of Light [21]
V/-8 = 4v
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8 0
3 years ago
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a. Determine whether the Mean Value Theorem applies to the function f (x )equals ln 15 xf(x)=ln15x on the given interval [1 comm
ivolga24 [154]

Answer:

(a)

The function f is continuous at [1,e] and differentiable at (1,e), therefore

the mean value theorem applies to the function.

(b)

c = e-1 \\ = 1.71828

Step-by-step explanation:

(a)

The function f is continuous at [1,e] and differentiable at (1,e), therefore

the mean value theorem applies to the function.

(b)

You are looking for a point c   such that

\frac{1}{c} = \frac{\ln(15e)-\ln(15*1)}{e-1} = \frac{\ln(15e/15)}{e-1} = \frac{\ln(e)}{e-1} = \frac{1}{e-1}

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5 0
3 years ago
Simplify<br> x + x + y y
kolezko [41]

Answer:

2x+2y

Step-by-step explanation:

x+x = 2x

y+y = 2y

2x+2y

4 0
4 years ago
Vera is using her phone.Its battery life is down to 2/5,and it drains another 1/9 every other. How many hours will her battery l
Margarita [4]

Let x be total hours of battery life. We have been given that battery life of Vera's phone is down to 2/5. So remaining battery life,

1-\frac{2}{5}=\frac{5-2}{5}=\frac{3}{5}

We have been also given that it drains another 1/9 every other hour. Now let us substitute our given information into an equation.

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Now we will solve for x.

x=\frac{3\cdot 9}{5}=\frac{27}{5}

x=(5+\frac{2}{5})hours

Let us convert 2/5 into minutes. We know 1 hour has 60 minutes.

60\cdot \frac{2}{5}=24\text{minutes}

Therefore, remaining battery life will be 5 hours and 24 minutes.



3 0
4 years ago
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Heyy could you help me out with this problem???​
vivado [14]

Answer:

C

Step-by-step explanation:

Because of all the variables in the side lengths, we don't have enough information to use side-angle-side similarity.

We do have two angles of one triangle congruent to two corresponding angles of the other triangle, so we can use angle-angle similarity.

Sides AE and AD are corresponding sides. Sides AC and AB are corresponding.

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