All categories

3 years ago

Bacteria come in different shapes true or false

Chemistry

2 answers:

Serhud [2]3 years ago

8 0

Answer:

true

Explanation:

siniylev [52]3 years ago

6 0

Answer:

true

Explanation:

some of the commonly observed shapes are

cocci : round

bacilli : rod-shaped

cocco-bacilli : rod- and round-shaped at the same time

Spirillum: spiral

These shapes also have different arrangements that you can check up for more understanding.

You might be interested in

What is the chemical equation for a reaction between copper (ll carbonate and heat?

tino4ka555 [31]

Copper (II) Carbonate + Heat yields copper (II) oxide and carbon dioxide
Molecular Equation: CuCo3 + heat > CuO + CO2

6 0

3 years ago

A weak base is titrated with a hydrochloric acid solution. What is the pH at the equivalence point?A) equal to pKaB) equal to 7C

zvonat [6]

Answer:

E) less than 7

Explanation:

pH is defined as the negative logarithm of the concentration of hydrogen ions.

Thus,

pH = - log [H⁺]

pH scale generally runs from 1 to 14 where pH = 7 represents neutral medium, pH < 7 represents acidic medium and pH > 7 represents basic medium.

Strong acids dissociate completely and when they react with base they form a salt of weak base and strong acid.

For example, $BOH$ is a weak base and $HCl$ is the hydrochloric acid.

So,

$BOH+HCl\rightarrow BCl+H_2O$

<u>Thus, the salt is of weak base and strong acid which corresponds to pH less than 7.</u>

4 0

4 years ago

The tabulated data were collected for this reaction:

erastovalidia [21]

Answer:

ai) Rate law, $Rate = k [CH_3 Cl] [Cl_2]^{0.5}$

aii) Rate constant, k = 1.25

b) Overall order of reaction = 1.5

Explanation:

Equation of Reaction:

$CH_{3} Cl (g) + 3 Cl_2 (g) \rightarrow CCl_4 (g) + 3 HCl (g)$

If $A + B \rightarrow C + D$ , the rate of backward reaction is given by:

$Rate = k [A]^{a} [B]^{b}\\k = \frac{Rate}{ [A]^{a} [B]^{b}}\\k = \frac{Rate}{ [CH_3 Cl]^{a} [Cl_2]^{b}}$

k is constant for all the stages

Using the information provided in lines 1 and 2 of the table:

$0.014 / [0.05]^a [0.05]^b = 00.029/ [0.100]^a [0.05]^b\\0.014 / [0.05]^a [0.05]^b = 00.029/ [2*0.05]^a [0.05]^b\\0.014 / = 0.029/ 2^a\\2^a = 2.07\\a = 1$

Using the information provided in lines 3 and 4 of the table and insering the value of a:

$0.041 / [0.100]^a [0.100]^b = 0.115 / [0.200]^a [0.200]^b\\0.041 / [0.100]^a [0.100]^b = 0.115 / [2 * 0.100]^a [2 * 0.100]^b\\$

$0.041 = 0.115 / [2 ]^a [2]^b\\ \[[2 ]^a [2]^b = 0.115/0.041\\ \[[2 ]^a [2]^b = 2.80\\\[[2 ]^1 [2]^b = 2.80\\\[[2]^b = 1.40\\b = \frac{ln 1.4}{ln 2} \\b = 0.5$