Answer:
The value of the heat capacity of the Calorimeter
= 54.4 ![\frac{J}{c}](https://tex.z-dn.net/?f=%5Cfrac%7BJ%7D%7Bc%7D)
Explanation:
Given data
Heat added Q = 4.168 KJ = 4168 J
Mass of water
= 75.40 gm
Temperature change = ΔT = 35.82 - 24.58 = 11.24 ° c
From the given condition
Q =
ΔT +
ΔT
Put all the values in above equation we get
4168 = 75.70 × 4.18 × 11.24 +
× 11.24
611.37 =
× 11.24
= 54.4 ![\frac{J}{c}](https://tex.z-dn.net/?f=%5Cfrac%7BJ%7D%7Bc%7D)
This is the value of the heat capacity of the Calorimeter.
answer:
in plants
Transport manufactured food from the leaves to others parts of the plant
Facilitates gaseous exchange through the stomata in the leaves to other parts of the plant
in animal
Exchange of respiratory gases across respiratory services
Excretion of nitrogenous waste in some unicellular organisms
Explanation:
Hope it benefit
Ozone is made up of 3 atoms of Oxygen and present in stratosphere of our atmosphere. It prevents us from "Ultraviolet rays" of Sunlight so it is an important form of oxygen or us
Hope this helps!
Answer:
3,29L
Explanation:
3.29L = V2
Formula: V1/T1 = V2/T2
--------------------
Given:
V1 = 3.0 L V2 = ?
T1 = 310 K T2 = 340 K
--------------------
Plugin:
(X stands in place of V2 just to make it easier to look at)
[3.0L / 310K = X / 340K]
(3.0L / 310K = 0.01L/K)
0.01L/K = X / 340K
(multiply 340K on both sides, it cancels out on the right)
0.01L/K * 340K = X
(0.01L/K * 340K = 3.29L)
**3.29L = X**
[or]
**3.29L = V2**