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Sergio [31]
3 years ago
5

How does an increase in temperature affect a gas when the volume is fixed? (Fixed means it stays the same.)

Chemistry
1 answer:
Ber [7]3 years ago
3 0

An increase in temperature at constant volume will increase the kinetic energy and the distance. Thus, option c is correct.

<h3>What is Gay-Lussac's law?</h3>

Gay-Lussac's law is the ideal gas law that defines the direct relation of the temperature to the pressure of the gas at a constant volume.

With an increase in the temperature of the gas, the pressure also rises causing the distance between the particle to expand by the increase in the kinetic energy.

Therefore, option c. the kinetic energy, particle distance, and the pressure increases with tempearture rise.

Learn more about Gay-Lussac's law here:

brainly.com/question/11387781

#SPJ1

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Which of the following is a chemical property? A. boiling point B. melting point C. density D. combustibility
nevsk [136]

Answer:

D

Explanation:

Because the other answers can not to be considered to be chemical properties.

Chemical means that the after the reaction the checal properties have changed in a way that it can no longer be called the same ad befor. In short, it can not be undone.

Burning a match is irriversable, meaning you can never go back to the previous situation because the chemical compounds have changed (dramatically).

Melted ice can be frozen again. Steam (evaporated water) can condensate to water which can be heated and can boil again. The chemical contents remain H2O.

6 0
3 years ago
I need help with #2. I don't know what law to use for problem.
bagirrra123 [75]
This uses something called the combined gas law. The combined gas law is as follows: (P1*V1/T1) = (P2*V2/T2)
According to question 2, you are given the following values initially:
P1 = 680 mm Hg * (1 atm/760 mm Hg) = 0.895 atm
V1 = 20.0 L
T1 = 293 K
STP or standard temperature and pressure implies that the other values we know are:
P2 = 1 atm
T2 = 273 K
Our unknown is V2
If we plug in our known values into the combined gas law:
(P1*V1/T1) = (P2*V2/T2)
(0.895 atm * 20.0 L)/293K = (1 atm * X liters)/273 K
0.0611 L*atm/K = (1 atm * X liters)/273 K
16.7 L = X liters
Therefore, the volume occupied at STP is 16.7 liters
This makes sense because the gas would occupy a smaller volume at a lower temperature, since the gas would have a lower average kinetic energy.
 
4 0
3 years ago
What is the pCu of the resulting solution if 20.00 mL of 0.08 M EDTA (H4Y) is added to 15.00 mL of 0.10 M CuSO4 and buffered at
katrin [286]

Answer:

The answer is "5.4".

Explanation:

BoH + HCL =BCL +H_2o \\\\At eq \\\\N_1V_1=N_2V_2 \\\\v_2=20 \ ml\\\\[BCL]=\frac{20 \times 0.08}{20+20}=0.04\\\\pH = \frac{1}{2} [pkw - pk_b - \log e]\\\\pk_b = 2 pH - Pkw + \Log C\\\\pK_b=5.4

3 0
3 years ago
What is the heat of vaporization of water?
andrew11 [14]
The molecules in liquid water are held together by relatively strong hydrogen bonds and its enthalpy of vaporization, 40.65 kJ/mol is more than five times the energy required to heat the same quantity of water from: 0 °C to 100 °C (cp = 75.3 J K−1 mol−1).

Hope this helps.
7 0
3 years ago
The emission spectrum of iodine is shown below. A line spectra with 2 purple lines, 6 blue lines, 3 light blue lines, 3 green-bl
Ilia_Sergeevich [38]

Answer: is C. on Edge 2020

Explanation:

5 0
3 years ago
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