Answer : Option D) Hot and dry with low growing shrubs.
Explanation : According to the attached image of the Biome, this particular biome displays the hot and dry climatic region along with low growing shrubs. A biomes are the way to divide the largely occurring flora and fauna in a particular place on the Earth's surface. These divisions are made on the basis of climatic patterns, soil types, and the animals and plants that are found to inhabit in that area.
The empirical formula of this compound is equal to .
To calculate the empirical formula of a compound, it is necessary to know the number of moles present.
Therefore, we will use the molar mass of iron and oxygen to find the amount of moles, so that:
Finally, as the empirical formula is composed of integers numbers of moles, just multiply the values by the smallest common factor to transform into an integer, so that:
O =>
Fe =>
So, the empirical formula of this compound is equal to
Learn more about empirical formula in: brainly.com/question/1363167
Answer:
The total pressure in the flask is 0,619 atm.
Explanation:
For the reaction:
2CH₄(g) + 3Cl₂(g) ⟶ 2 CH₃Cl(g) + 2HCl(g) + 2Cl⁻(g)
The moles of CH₄ in 295 mL at STP are:
n = PV/RT
Where P is pressure (1 atm), V is volume (0,295L), R is gas constant (0,082atmL/molK) and T is temperature (273,15 K)
Replacing, moles of CH₄ are <em>0,0132 moles</em>
In the same way, moles of chlorine are <em>0,0324 moles</em>
As 3 moles of Cl₂ react with 2 moles of CH₄, for a total reaction of 0,0132 moles of CH₄ you need:
0,0132 moles CH₄ × = <em>0,0198 moles Cl₂. </em>That means that 0,0324-0,0198 = <em>0,0126 moles of Cl₂ are in excess.</em>
As the reaction reaches in 77%, the moles of CH₄ that don't react are:
0,0132×(100%-77%)= <em>3,036x10⁻³ moles of CH₄</em>
Also, the moles of Cl₂ that don't react are:
0,0126 + 0,0198×(100%-77%)= <em>0,0172 moles of Cl₂</em>
The moles produced of each compound are:
0,0132×77% × = <em>0,0102 moles of CH₃Cl -</em><em>that are the same moles of HCl and Cl⁻</em><em>-</em>
Thus, total moles in the flask are:
<em>3,036x10⁻³ moles of CH₄ + 0,0172 moles of Cl₂ + 0,0102 moles of CH₃Cl + 0,0102 moles of HCl + 0,0102 moles of Cl⁻ = </em><em>0,0507 total moles</em>
As the volume of the flask is 2,00L and the final temperature is 298 K. The total pressure in the flask is:
P = nRT/V
<em>P = 0,619 atm</em>
<em> </em>
I hope it helps!
Answer:
Approximately 75%.
Explanation:
Look up the relative atomic mass of Ca on a modern periodic table:
There are one mole of Ca atoms in each mole of CaCO₃ formula unit.
Calculate the mass ratio of Ca in a pure sample of CaCO₃:
.
Let the mass of the sample be 100 g. This sample of CaCO₃ contains 30% Ca by mass. In that 100 grams of this sample, there would be of Ca atoms. Assuming that the impurity does not contain any Ca. In other words, all these Ca atoms belong to CaCO₃. Apply the ratio
:
.
In other words, by these assumptions, 100 grams of this sample would contain 75 grams of CaCO₃. The percentage mass of CaCO₃ in this sample would thus be equal to:
.