All categories

3 years ago

Complete the chemical reaction that occurs when dimethylamine (ch3)2nh reacts with water.

1 answer:

3 0

Dimethyl amine is Base. The basic character of it is due to the presence of lone pair of electron on nitrogen atom. The strength of amines is basically due to the presence of alkyl group attached to nitrogen atom. These alkyl groups donates electron to nitrogen atom hence increasing electron density on nitrogen and increasing its basic character.

When dimethylamine ( Kb = 5.9 × 10⁻⁴) is reacted with water it abstracts proton from water molecule convertion it into Hydroxide Ion (i.e ⁻OH). The reaction is as follow,

(CH₃)₂N + H₂O → (CH₃)₂N⁺H + ⁻OH

You might be interested in

Determine the redox reaction represented by the following cell notation: Mg(s) | Mg2 (aq) || Cu2 (aq) | Cu(s)

mrs_skeptik [129]

Oxidation: Mg (s) —> Mg2+ (aq) + 2e
reduction: Cu2+ (aq) +2e —> Cu(s)

redox reaction: Mg(s) + Cu2+(aq)—> Mg2+(aq) + Cu(s)

6 0

3 years ago

SPACE SCIENCE If the Milky Way galaxy were a pizza, would the Earth be in the cheese or on the crust? Justify your answer.

AURORKA [14]

Answer:

Crust

Explanation:

we are part of one of the arms of the galaxies mostly because the centre is way to dense

7 0

3 years ago

What is Alkaline and acid

Lunna [17]

Answer:

Alkaline is a substance that is over the pH of 7. an acid is a substance that is lower than the pH of 7

When universal indicator is put into an alkaline substance it will turn blue/purple/black. If it is an acid the substance will turn red/orange/yellow

The same will happen if litmus paper is used instaed. If the paper turns blue/purple/black it means that the substance is an alkaline. If the paper turns red/orange/yellow it means that the substance is an acid

If the substance or the litmus paper turns green it means that it is neutral (It has the pH of 7)

Your welcome

please mark brainliest

8 0

3 years ago

In a certain industrial process involving a heterogeneous catalyst, the volume of the catalyst (in the shape of a sphere) is 10.

mamaluj [8]

Answer:

Explanation:

We know that the

reaction catalyzing power of a catalyst ∝ surface area exposed by it

Given

volume V1= 10 cm^3

⇒ $\frac{4}{3} \pi r^3= 10$

hence r= 1.545 cm

also, surface area S1= $4\pi r^2$

now when the sphere is broken down into 8 smaller spheres

S2= 8×4πr'^2

now, equating V1 and V2 ( as the volume must remain same )

$\frac{4}{3}\pi r^3=8\times\frac{4}{3} \pi r'^3$

and solving we get

r'= r/2

therefore, S2= $8\times4\pi\frac{r}{2}^2$

S2= $2\times4\pi r^2$

S2= 2S1

hence the correct answer is

. The second run has twice the surface area.

8 0

3 years ago

Calculate the percent ionization of nitrous acid in a solution that is 0.311 M in nitrous acid (HNO2) and 0.189 M in potassium n

Alla [95]

HNO2 =====> H+ + NO2-
Initial concentration = 0.311
C = -x,x,x 
E = 0.311-x,x,x

KNO2 ====>K+ + NO2-
Initial concentration = 0.189 
C= -0.189,0.189,0.189 
E = 0,0.189,0.189

6 0

3 years ago