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Darya [45]
3 years ago
8

Change the fraction 1/5 to a percent.

Mathematics
2 answers:
nalin [4]3 years ago
7 0
20 percent because you could make it out of 100 so 1 x 20 = 20 and 5 x 20 = 100so I would say 20 percent
denis23 [38]3 years ago
5 0
\frac{1}{5} \cdot 100 \ \% = 0.2 \cdot 100 \ \% = 20 \ \%.
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Tim says that every time you mutiply two
Sunny_sXe [5.5K]

Answer:

I disagree

Step-by-step explanation:

This is not true because when you multiply a number by one. It will give you its number. It may be a larger number than 1 but it is not bigger than both numbers. Also if you multiply 0 by a number. It will eventually give you the answer 0 .It will be smaller than the number you started with. eg   100x0 = 0

4 0
2 years ago
Can someone help me with the graphing part??
vlabodo [156]

Answer:

In the picture above.

Step-by-step explanation:

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6 0
3 years ago
4. The Blackhawk Eagles scored 4 points more than the Lane Vikings. The
konstantin123 [22]

Answer:

Lane Viking's Score is 17

Black Eagles's Score  is 21

Step-by-step explanation:

Let Lane Viking's Score be x and Black Eagles's Score be y.

Black Eagles's Score = 4+ Lane Viking's Score

so y = 4 + x    (Equation 1)

Total Score = 38

Black Eagles's Score + Lane Viking's Score = 38

so y + x =38     (Equation 2)

Putting y's value from Equation 1 in Equation 2

4 + x + x = 38

2x = 38-4

x=34/2

x=17

Putting value of x in Equation 1

y = 4 + 17

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7 0
3 years ago
Find the area of the triangle below. Show as much work as possible. Label your answer appropriately.
Dmitry [639]

Answer:

Area=\frac{5}{12}x^2

Step-by-step explanation:

The area of a triangle is given by:

Area=\frac{1}{2}*base*height

From the diagram base=\frac{5}{6}x,and,height=x

We substitute into the formula to get:

Area=\frac{1}{2}*\frac{5}{6}x*x

This implies that:

Area=\frac{5}{12}x^2

3 0
3 years ago
Determine an equation of a Quadratic function
Pepsi [2]

Answer:

y = -4x² + 32x - 48

Step-by-step explanation:

The standard form of a quadratic equation is  

y = ax² + bx + c

We must find the equation that passes through the points:

(2, 0), (6,0), and (3, 12)

We can substitute these values and get three equations in three unknowns.

0 = a(2²) + b(2) + c

0 = a(6²) + b(6) + c

12 = a(3²) + b(3) + c

We can simplify these to get the system of equations:

(1)   0 =    4a + 2b + c

(2)  0 = 36a + 6b + c

(3) 12 =   9a + 3b + c

Eliminate c from equations (1) and (2). Subtract (1) from (2).

(4) 0 = 32a + 4b

Eliminate c from equations (2) and (3). Subtract (3) from (2).

(5) -12 = 27a - 3b

Simplify equations (4) and (5).

(6)  0 = 8a + b

(7) -4 = 9a  - b

Eliminate b by adding equations (6) and (7).

(8) a = -4

Substitute (4) into (6).

    0 = -32 + b

(9) b =  32

Substitute a and b into (1)

0 = 4(-4) + 2(32) + c

0 = -16 + 64 + c

0 = 48 + c

c = -48

The coefficients are

a= -4, b = 32, c = -48

The quadratic equation is

y = -4x² + 32x - 48

The diagram below shows the graph of your quadratic equation and the three points through which it passes.

4 0
3 years ago
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