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Sever21 [200]
3 years ago
12

State all integer values of x in the interval (2,8) that satisfy the following inequality:

Mathematics
1 answer:
lidiya [134]3 years ago
3 0

Answer:

3,4,5,6 and 7

Step-by-step explanation:

Given

5x + 4 \ge 19

Required

State the values of x within 2 and 8

5x + 4 \ge 19

Collect Like Terms

5x \ge 19 - 4

5x \ge 15

Divide both sides by 5

\frac{5x}{5} \ge \frac{15}{5}

x \ge 3

(2,8) is an open interval which means that 2 and 8 are not inclusive of the values of x.

So:

The values of x \ge 3 are: 3,4,5,6 and 7

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What is the square root of 3 squared
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8 0
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Which expression is equivalent to -9x^-1y^-9/-15x^5/y^3? Assume x=0,y=0
Juliette [100K]

Answer:

B

Step-by-step explanation:


8 0
3 years ago
Solve the following system of equations<br><br> 3x - 2y =5<br><br> -2x - 3y = 14
stepladder [879]

Answer:

x = -1 and y = -4

Step-by-step explanation:

It is given that,

3x - 2y = 5     ----(1)

-2x - 3y = 14 ------(2)

<u>To find the solution of equations</u>

(1) * 2 ⇒

6x - 4y = 10  -----(3)

(2) * 3 ⇒

-6x - 9y =  42   ----(4)

eq(3) + eq(4) ⇒

6x - 4y = 10  -----(3)

<u>-6x - 9y =  42 </u>  ----(4)

 0   - 13y = 52

y = 52/(-13) = -4

Substitute the value of y in eq(1)

3x - 2y = 5     ----(1)

3x - (2 * -4) = 5

3x  +8 = 5

3x = 5 - 8 = -3

x = -3/3 = -1

Therefore x = -1 and y = -4

5 0
3 years ago
Read 2 more answers
How would you find the zero of f (x)=16x^4 - 9x^2
krok68 [10]
f (x) = 16x ^ 4 - 9x ^ 2 \\ \\16x ^ 4 - 9x ^ 2=0\\ \\x^2(16x^2-9)=0 \\ \\x^2 =0 \ \ or \ \ 16x^2-9=0\\ \\ x=0 \ \ or \ \ (4x-3)(4x+3)=0\\ \\ x=0 \ \ or \ \  4x-3=0 \ \ or \ \ 4x+3 =0\\ \\x=0 \ \ or \ \  4x=3 \ \ / :4 \ \ or \ \ 4x=-3\ \ / :4 \\ \\ x=0 \ \ or \ \   x=\frac{3}{4} \ \ or \ \  x=-\frac{3}{4}
3 0
3 years ago
Read 2 more answers
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