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3 years ago

14

What tells you which operation to perform first... I really need the answer like now!! thank you!

2 answers:

BaLLatris [955]3 years ago

7 0

PEMDAS----- many people remember it as Please Excuse My Dear Aunt Sally. It stand for (Parentheses), exponents, multiply, divide, addition, and subtraction. It should be done in this order.

Vinvika [58]3 years ago

5 0

PEMDAS : Parentheses, Exponents, Multiplication, Division, Addition, Subtraction. That is the general rule of things and in the order of which goes first.
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If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x

Andrei [34K]

Answer:

$\large\boxed{A.\ (x+6)^2+(y+10)^2=20}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10$

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute (-6, -10) and (-8, -6):

$r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}$

Finally we have

$(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20$

5 0

4 years ago

Read 2 more answers

Rachel bakes a number of loaves of garlic bread each day. She uses 3 cops of flour for each loaf of bread. Write an algebraic ex

mart [117]

Z×3=x
I used that because we dont know how much she bakes each day and that would be multiplied by 3 which would equal somthing

5 0

3 years ago

Read 2 more answers

Does anyone know where the a in front of the parentheses for the LCD : a(a+5)(a-6) came from?

lukranit [14]

Answer:

See below

Step-by-step explanation:

If you factor $a^2-a-30$ you get $\left(a^2+5a\right)+\left(-6a-30\right)$

= $a(a+5)-6(a+5)$

= $a(a+5)(a-6)$

That's where the a comes in

Not sure if that answers your question

8 0

2 years ago

Please help solve this SAT math problem. I have 4 more like these so need help with this so that I can solve the rest by myself.

stealth61 [152]

The notation just means

(f/g)(-4) = f(-4) / g(-4)

If f(x) = x² + 2 and g(x) = 1 - 3x, then

f(-4) = (-4)² + 2 = 16 + 2 = 18

g(-4) = 1 - 3 (-4) = 1 + 12 = 13

and so

(f/g)(-4) = 18/13

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3 years ago

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