1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
elena55 [62]
3 years ago
12

In circle Q angle PSR equals 47 degrees, find the angle measure of minor arc PR​

Mathematics
1 answer:
ziro4ka [17]3 years ago
7 0

Answer:

I think

Step-by-step explanation:

East is yet to read this back

You might be interested in
What is 20-4? My brother doesnt believe that the answer is 25 and he keeps saying its 16 please tell me i am correct
babymother [125]

Answer:

Dont tell me you're trolling. Anyway, its 16

3 0
2 years ago
Read 2 more answers
John, Sally, and Natalie would all like to save some money. John decides that it
brilliants [131]

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2)  y=100x+300

Part 3) \$12,300

Part 4) \$2,700

Part 5) Is a exponential growth function

Part 6) A=6,000(1.07)^{t}

Part 7) \$11,802.91

Part 8)  \$6,869.40

Part 9) Is a exponential growth function

Part 10) A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}

Part 11)  \$13,591.41

Part 12) \$6,107.01

Part 13)  Natalie has the most money after 10 years

Part 14)  Sally has the most money after 2 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

y=mx+b

The slope is equal to

m=\$100\ per\ month

The y-intercept or initial value is

b=\$300

so

y=100x+300

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

see part 1)

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

so

10\ years=10(12)=120 months

For x=120 months

substitute in the linear equation

y=100(120)+300=\$12,300

Part 4) How much money will John have after 2 years?

Remember that

1 year is equal to 12 months

so

2\  years=2(12)=24\ months

For x=24 months

substitute in the linear equation

y=100(24)+300=\$2,700

Part 5) What type of exponential model is Sally’s situation?

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt} 

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

P=\$6,000\\ r=7\%=0.07\\n=1

substitute in the formula above

A=6,000(1+\frac{0.07}{1})^{1*t}\\  A=6,000(1.07)^{t}

therefore

Is a exponential growth function

Part 6) Write the model equation for Sally’s situation

see the Part 5)

Part 7) How much money will Sally have after 10 years?

For t=10 years

substitute  the value of t in the exponential growth function

A=6,000(1.07)^{10}=\$11,802.91 

Part 8) How much money will Sally have after 2 years?

For t=2 years

substitute  the value of t in the exponential growth function

A=6,000(1.07)^{2}=\$6,869.40

Part 9) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt} 

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

P=\$5,000\\r=10\%=0.10

substitute in the formula above

A=5,000(e)^{0.10t}

Applying property of exponents

A=5,000(1.1052)^{t}

 therefore

Is a exponential growth function

Part 10) Write the model equation for Natalie’s situation

A=5,000(e)^{0.10t}    or  A=5,000(1.1052)^{t}

see Part 9)

Part 11) How much money will Natalie have after 10 years?

For t=10 years

substitute

A=5,000(e)^{0.10*10}=\$13,591.41

Part 12) How much money will Natalie have after 2 years?

For t=2 years

substitute

A=5,000(e)^{0.10*2}=\$6,107.01

Part 13) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

Part 14) Who will have the most money after 2 years?

Compare the final investment after 2 years of John, Sally, and Natalie

Sally has the most money after 2 years

3 0
3 years ago
Alan sells beaded necklaces. Each large necklace sells for $5.70 and each small necklace sells for $5.10. How much will he earn
inysia [295]
Alan will make $28.50 from 5 large necklaces and $15.30 from 3 small necklaces. $43.80 in total :)
6 0
3 years ago
Read 2 more answers
Why is the answer A?
Marina86 [1]

Answer:

B) 2 frozen dinners and 2 dozen jelly doughnuts

Step-by-step explanation:

Calculate the total utility for each option.

A) 46

B) 32 + 21 = 53

C) 16 + 30 = 46

D) 28

Option B has the highest total utility.

4 0
3 years ago
1) radius = 2 feet height = 4 feet
LekaFEV [45]

Answer:

R=2

Step-by-step explanation:

2x2=4

8 0
3 years ago
Read 2 more answers
Other questions:
  • You pack sandwiches for a mountain hike with your friends. Each sandwich takes 2 slices of bread, and each hiker eats one sandwi
    8·2 answers
  • Write nine hundred and eight tenths as a decimal number.
    11·1 answer
  • 9m=6 what does m = in this equation ?
    11·2 answers
  • Given: (x + 5)^2 + (y - 3)^2 = 144, where is the center of the circle? *
    14·1 answer
  • (Apex!) Select the two values of x that are roots of this equation 3x-5=-2x^2
    5·1 answer
  • Katie says the graph of y=8 . (1/2)^x is the same as the graph of f(x)=8 . (1/2)^x. Do you agree? Explain your reasoning.
    10·2 answers
  • Which set of fractions is ordered from least to greatest?
    14·1 answer
  • C(t)=26(0.87)^(t) answer
    7·1 answer
  • Find and x and y <br> PLEASE HELP
    11·1 answer
  • Please help me with this
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!