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elena55 [62]
3 years ago
12

In circle Q angle PSR equals 47 degrees, find the angle measure of minor arc PR​

Mathematics
1 answer:
ziro4ka [17]3 years ago
7 0

Answer:

I think

Step-by-step explanation:

East is yet to read this back

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What is an equation of the line that passes through the points (1, -7) and (-4, 8)?
melomori [17]
<h2>Answer:    y + 7  =  -3 (x - 1)</h2>

Step-by-step explanation:

The slope of the line (m) = (y₂ - y₁) ÷ (x₂ - x₁)  

                                       

                                          =  (- 7 - 8) ÷ ( 1 - (- 4))

                                         =    - 15  ÷  5

                                         =  - 3

We can now use the point-slope form to write the equation for this line:

        y - y₁ = m(x - x₁) where (x₁ , y₁) = (1, -7)

             y - (-7) =  -3 ( x  -  1)

              y + 7  =  -3 (x - 1)

3 0
3 years ago
There are approximately 15 milliliters (mL) in 1 tablespoon (tbsp). Which expression can be used to find the approximate number
Greeley [361]
We develop the ratio between the number of milliliters present in 1 tablespoon and that is,
                               15 mL: 1 tablespoon
We let x be the number of millileter in 3 tbsp and it can be determined through the equation below.
                                x = 3 tbsp x (15 mL/ 1 tbsp) = 45 mL
Therefore, there are 45 mL in 3 tbsp.
3 0
3 years ago
Determine the mass of a solid steel ball that has a diameter of 10 cm. The density of pure steel is 8.09 g/cm3
Basile [38]

Answer:

<em>The mass of the steel ball is 4,235.9 gr</em>

Step-by-step explanation:

<u>Density</u>

The density ρ of a substance is a measure of its mass per unit volume:

\displaystyle \rho=\frac{m}{V}

If the density and the volume are given, the mass can be calculated by solving the above formula for m:

m=\rho.V

We know the density of pure steel ρ=8.09 gr/cm3 and the diameter of a solid steel ball d=10 cm.

We need to calculate the volume of the sphere:

The volume of a sphere of radius r is given by:

\displaystyle V=\frac{4}{3}\cdot \pi\cdot r^3

The radius is half the diameter: r= 10/2 = 5 cm. Thus:

\displaystyle V=\frac{4}{3}\cdot \pi\cdot 5^3

Calculating:

V=523.6\ cm^3

The mass is:

m=8.09 gr/cm^3 \cdot 523.6\ cm^3

m=4,235.9 gr

The mass of the steel ball is 4,235.9 gr

4 0
3 years ago
What is d and how would I find its value
denis23 [38]
D-value (meteorology) in meteorology refers to the deviation of actual altitude along a constant pressure surface from the standard atmosphere altitude of that surface.
3 0
3 years ago
Find an integer $x$ such that $\frac{2}{3} &lt; \frac{x}{5} &lt; \frac{6}{7}$.
alexandr1967 [171]

Answer:

4

Step-by-step explanation:

It's AoPS question

5 0
2 years ago
Read 2 more answers
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