Lines are parallel if and only if there slopes are the same
the slope will be m in the equation y=mx+b notice that the coefficient of y is 1
a)y=3/5x+1
b)5y=3x-2---> divide the whole equation by 5-->y=3/5-(2/5)
c)10x-6y=-4-->solving for y--->-6y=-4-10x--->dividing by -6--->y=(-10/-6)x-(4/-6)
so a and b are parallel
for the second question
a)4x-3y=2---->-3y=2-4x---->y=(2/-3)+(4/3)x
b)3x+4y=-1--->4y=-1-3x---->y=(-1/4)-(3/4)x
c)4y-3x=20--->4y=20+3x--->y=5+(3/4)x
so no parallel lines in the second question
Answer <u>(assuming the question allows it to be written in slope-intercept form)</u>:

Step-by-step explanation:
1) First, find the slope of the equation. Use the slope formula
, substitute the given points' x and y values, and simplify:

Thus, the slope is
.
2) Now, use the point-slope formula
and substitute real values for
,
, and
.
Since
represents the slope, substitute
in its place. Since
and
represent the x and y values of a point the line crosses, use the x and y values of any one of the given points to substitute into the formula. (Either one is fine. I chose (2,-3).) Then, isolate y to put it into slope-intercept form and find the answer:

2 (2x - (2 - 2y + 3x) + 4y) =
2 (2x - 2 - 2y + 3x + 4y) =
2 (5x + 2y - 2) =
10x + 4y - 4
This was my solution.
N26? I'm guessing. Distribute the 2 into the n 3 and the 4 in the n 5. Is that helpful?
Answer:
its=> 3×4=-3-6(use a caculator now)