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elena55 [62]
3 years ago
8

A cook needs

Mathematics
1 answer:
GREYUIT [131]3 years ago
8 0

1 cup = 0.5 pints

3 x 0.5 = 1.5 pints = 1 1/2 pints

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Adam buys a cubical box to mail a package. The volume of this box is 216 cubic inches. What is the length of one side
BartSMP [9]
Let V=216
formula for volume=a^3
V=a^3
216=a^3
now by taking cubert on both sides
cuberoot(216)=cuberoot(a^3)
a=6
so the length of one side will be 6m
7 0
3 years ago
Find the distance of the line segment joining the two points (-4 /2 - /12) and (/32, 2/3)
astraxan [27]

Answer: 4\sqrt{3} .

Step-by-step explanation:

Distance formula : Distance between points (a,b) and (c,d) is given by :-

D=\sqrt{(d-b)^2+(b-a)^2}

Distance between points (-4\sqrt{2},\sqrt{12}) \text{ and }(-\sqrt{32}, 2\sqrt{3}).

D=\sqrt{(2\sqrt{3}-(-\sqrt{12}))^2+(-\sqrt{32}-(-4\sqrt{2}))}\\\\=\sqrt{(2\sqrt{3}+\sqrt{2\times2\times3})^2+(-\sqrt{4\times4\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}-\sqrt{2^2\times3})^2+(-\sqrt{4^2\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}+2\sqrt{3})^2+(-4\sqrt{2}+4\sqrt{2})^2}\\\\=\sqrt{(4\sqrt{3})^2+0}\\\\=4\sqrt{3}\text{ units}

Hence, the correct option is 4\sqrt{3} .

3 0
3 years ago
In a parallelogram a diagonal of the length 20 cm is perpendicular to one of the sides. Find the longer side of parallelogram if
riadik2000 [5.3K]
All the sides are 20 cm resulting in the perimeter being 80
7 0
3 years ago
Read 2 more answers
How many terms are in the arithmetic sequence 9, 2, −5, . . . , −187?
Fantom [35]
9, 2, -5... so is going down by 7 each time, meaning the "common difference" is -7.

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=9\\
d=-7\\
a_n=-187
\end{cases}
\\\\\\
-187=9+(n-1)(-7)\implies -187=9-7n+7
\\\\\\
7n=9+7+187\implies 7n=203\implies n=\cfrac{203}{7}\implies \boxed{n=29}
4 0
3 years ago
The expression \dfrac12bh
mariarad [96]

Answer:

2 one.

Step-by-step explanation:

3 0
3 years ago
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