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elena55 [62]
4 years ago
8

A cook needs

Mathematics
1 answer:
GREYUIT [131]4 years ago
8 0

1 cup = 0.5 pints

3 x 0.5 = 1.5 pints = 1 1/2 pints

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What function is graphed below?<br><br><br><br> y = 2x<br> y = x + 3<br> y = 2x + 3<br> y = 2x + 2
vagabundo [1.1K]

Answer:

y=2x+3

Step-by-step explanation:

The coefficient has to be 2, since the graph has a slope of 2, and the constant has to be 3 because the y- intercept is 3.

y=2x+3

3 0
3 years ago
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Write the equation of a line with slope of 5/6 , and x-intercept of −8 in point-slope form.
babymother [125]

Answer:  y-0 = \frac{5}{6}(x+8)

==================================================

Explanation:

Point-slope form is

y - y_1 = m(x - x_1)\\\\

where m is the slope and (x_1,y_1) is the point the line goes through.

We're given the slope of m = 5/6, and we want the line going through (-8,0) which is the x-intercept -8. The x-intercept always occurs when y = 0.

So,

y - y_1 = m(x - x_1)\\\\y - 0 = \frac{5}{6}(x - (-8))\\\\y - 0 = \frac{5}{6}(x + 8)\\\\

We can replace the y-0 with y; however, I'm going to keep that 0 so that the equation better matches the point-slope form.

7 0
3 years ago
Calvin paints pictures and sells them at art shows. He charges $ 56.25 for a large painting. He charges $25.80 for a small paint
yarga [219]
He made $ 394.90 because you need to add all the large paintings then the small ones then add them all
8 0
3 years ago
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In a 45-45-90 triangle, the length if the hypotenuse is 11. Find the length of one of the legs
Scrat [10]
The answer is B, picture shows how to solve it although the answer is written slightly different

6 0
3 years ago
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F(x)=(x-6)e^-3x find the interval in which f(x) is increasing, the intervals on which f(x) is decreasing, and the local extrema
Over [174]
\bf f(x)=(x-6)e^{-3x}\\\\&#10;-----------------------------\\\\&#10;\cfrac{dy}{dx}=1\cdot e^{-3x}+(x-6)-3e^{-3x}\implies \cfrac{dy}{dx}=e^{-3x}[1-3(x-6)]&#10;\\\\\\&#10;\cfrac{dy}{dx}=e^{-3x}(19-3x)\implies \cfrac{dy}{dx}=\cfrac{19-3x}{e^{3x}}

set the derivative to 0, solve for "x" to get any critical points
keep in mind, setting the denominator to 0, also gives us critical points, however, in this case, the denominator will never be 0, so... no critical points from there

there's only 1 critical point anyway, and do a first-derivative test on it, check a number before it and after it, to see what sign the derivative has, and thus, whether the graph is going up or down, to check for any extrema
5 0
3 years ago
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