Question

In a 45-45-90 triangle, the length if the hypotenuse is 11. Find the length of one of the legs

Answer 1

Answer:

$\frac{11\sqrt{2}}{2}$

Step-by-step explanation:

In a 45-45-90 triangle, the length if the hypotenuse is 11

WE use the common ratio of 45-45-90 degree triangle

common ration is x: x: x sqrt(2)

x sqrt(2) is the length of the hypotenuse

$x\sqrt{2} = 11$

Divide by sqrt(2) on both sides

$x= \frac{11}{\sqrt{2}}$

To rationalize the denominator, multiply by sqrt(2) at the top and bottom

sqrt(2) * sqrt(2) = 2

$x= \frac{11\sqrt{2}}{2}$

Answer 2

The answer is B, picture shows how to solve it although the answer is written slightly different