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Basile [38]
3 years ago
10

337,016 in expanded form using exponents

Mathematics
1 answer:
Naddik [55]3 years ago
5 0

The answer is three hundred thirty-seven thousand sixteen

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Pls help me and can someone help be my touter
ELEN [110]
Wouldn't it be 6 cm, 8 cm, 10 cm?
6 0
4 years ago
Which linear function represents the line given by the point-slope equation y – 8 = y minus 8 equals startfraction one-half endf
Marina CMI [18]

The linear function which represents the line given by the point-slope equation is (B) f(x)=\frac{1}{2} x+6.

<h3>What is a linear function?</h3>
  • The word linear function in mathematics refers to two distinct but related concepts.
  • A linear function in calculus and related fields is a function whose graph is a straight line, that is, a polynomial function of degree zero or one.

To find the linear function which represents the line given by the point-slope equation:

Given: y-8=\frac{1}{2} (x-4)

Distribute the right side:

y-8=\frac{1}{2} (x)-\frac{1}{2} 4\\y-8=\frac{1}{2} x-2

Adds 8 on both sides:

y=\frac{1}{2}x-2+8\\y=\frac{1}{2}x+6

Convert to function notation:

f(x)=y\\f(x)=\frac{1}{2} x+6

Therefore, the linear function which represents the line given by the point-slope equation is (B) f(x)=\frac{1}{2} x+6.

Know more about linear functions here:

brainly.com/question/15602982

#SPJ4

The complete question is given below:

Which linear function represents the line given by the point-slope equation y – 8 = y minus 8 equals start fraction one-half end fraction left-parenthesis x minus 4 right-parenthesis. (x – 4)?

A) F(x) = f(x) equals StartFraction one-half EndFraction x plus 4.X + 4

B) f(x) = f(x) equals StartFraction one-half EndFraction x plus 6.

C) X + 6 f(x) = f(x) equals StartFraction one-half EndFraction x minus 10.X –10

D) f(x) = f(x) equals StartFraction one-half EndFraction x minus 12.X – 12

3 0
1 year ago
Glen spins the spinner below.
antiseptic1488 [7]
The answer is: not likely. There isn’t much of a chance !
6 0
2 years ago
Convert the equation:
Licemer1 [7]

Answer:

(x+1)²/6 - (y+3)²/12 = 1

Step-by-step explanation:

The standard form of writing the equation of an hyperbola is expressed as;

(x-h)²/a² - (y-b)²/b² = 1 where (h,k) is the centre of the hyperbola.

Given the equation:

6x²-3y²+12x-18y-3 = 0

We are to convert it to the standard form of writing the equation of a hyperbola.

Collecting the like terms will give;

(6x²+12x)-(3y²+18y)-3 = 0

Divide through by 3

(2x²+4x)-(y²+6y)-1 = 0

Completing the square of the equation in parenthesis and adding the constants to the other side of the equation:

(2x²+4x)-(y²+6y+(6/2)²)-1 = 0+(6/2)²

(2x²+4x)-(y²+6y+9)-1 = 9

2x²+4x -{(y+3)²} = 9+1

2x²+4x - (y+3)² = 10

Divide through by 2

x²+2x -(y+3)²/2 = 5

(x²+2x+(2/2)²)-(y+3)²/2 = 5+(2/2)²

(x²+2x+1) - (y+3)²/2 = 5+1

(x+1)²-(y+3)²/2 = 6

Divide through by 6

(x+1)²/6 - (y+3)²/12 = 1

The resulting equation is the required standard form of a hyperbola with centre at (-1, -3)

8 0
3 years ago
100 POINTS !!! Find the axis of symmetry and the vertex of the graph of y = 6x2 − 24x + 11. x = 2; (2, −13) x = 4; (4, 11) x = −
xxTIMURxx [149]

Let's see

\\ \rm\rightarrowtail y=6x^2-25x+11

Graph attached

  • vertex(-2,-13)

Axis of symmetry

  • x=-2

7 0
2 years ago
Read 2 more answers
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