Cam bounces a ball 2.528 feet in front of his feet. The path of the ball from the time it hits the ground until it lands on the floor is represented by f(x)= -(x-7)^2+20 Assuming that Cam's feet located at the origin, (0,0), what is the maximum height of the ball in (feet)?
2 answers:
Answer:
20 feet
Step-by-step explanation:
Since the term -(x-7)^2 is negative, the largest height that the ball can reach is when this term is 0. 0+20=20, meaning that the highest the ball can go is 20 feet. Hope this helps!
Answer: 20 feet
<u>Step-by-step explanation:</u>
The vertex form of a quadratic equation is: y = a(x - h)² + k
where (h, k) is the vertex
h is the axis of symmetry (time at which maximum height is reached)
k is the maximum height
Given: y = -(x - 7)² + 20
--> h = 7, k = 20
therefore, the maximum height of the ball is 20
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