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artcher [175]
2 years ago
14

184 is what percent more than 148

Mathematics
1 answer:
Alika [10]2 years ago
7 0
It is 36 percent more
You might be interested in
What fraction represents 0.1875 ft?
aliya0001 [1]

Answer:

There is not much that can be done to figure out how to write 0.1875 as a fraction, except to literally use what the decimal portion of your number, the .1875 , means. Since there are 5 digits in 1875 , the very last digit is the "100000th" decimal place. So we can just say that .1875 is the same as 1875/100000.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
At 1 p.m., the number of cars in a parking lot is 78. Given the formula found in the first part of the question, An=78⋅1.09n, es
Harrizon [31]

Answer:

At 6 p.m., the number of cars in a parking lot is 120

Step-by-step explanation:

At 1 p.m., the number of cars in a parking lot is 78.

Given,

A_n=78\cdot 1.09^n

Note that

A_0=78\cdot 1.09^0=78\cdot 1=78

So, 1 p.m. goes for n = 0, then

6 p.m. goes for n = 5

Thus,

A_5=78\cdot 1.09^5\approx 120

4 0
3 years ago
Each bill at a restaurant includes an 18% tip. Which of the following bill amounts and tips could be from this restaurant? Selec
jenyasd209 [6]

Answer:

1. Yes

2. No

3. No

4. Yes

4 0
3 years ago
Read 2 more answers
How many different ways can you make 82 cents using current u.s. currency
andrew11 [14]
 <span>You can probably just work it out. 

You need non-negative integer solutions to p+5n+10d+25q = 82. 

If p = leftovers, then you simply need 5n + 10d + 25q ≤ 80. 


So this is the same as n + 2d + 5q ≤ 16 

So now you simply have to "crank out" the cases. 

Case q=0 [ n + 2d ≤ 16 ] 

Case (q=0,d=0) → n = 0 through 16 [17 possibilities] 
Case (q=0,d=1) → n = 0 through 14 [15 possibilities] 
... 
Case (q=0,d=7) → n = 0 through 2 [3 possibilities] 
Case (q=0,d=8) → n = 0 [1 possibility] 

Total from q=0 case: 1 + 3 + ... + 15 + 17 = 81 

Case q=1 [ n + 2d ≤ 11 ] 
Case (q=1,d=0) → n = 0 through 11 [12] 
Case (q=1,d=1) → n = 0 through 9 [10] 
... 
Case (q=1,d=5) → n = 0 through 1 [2] 

Total from q=1 case: 2 + 4 + ... + 10 + 12 = 42 

Case q=2 [ n + 2 ≤ 6 ] 
Case (q=2,d=0) → n = 0 through 6 [7] 
Case (q=2,d=1) → n = 0 through 4 [5] 
Case (q=2,d=2) → n = 0 through 2 [3] 
Case (q=2,d=3) → n = 0 [1] 

Total from case q=2: 1 + 3 + 5 + 7 = 16 

Case q=3 [ n + 2d ≤ 1 ] 
Here d must be 0, so there is only the case: 
Case (q=3,d=0) → n = 0 through 1 [2] 

So the case q=3 only has 2. 

Grand total: 2 + 16 + 42 + 81 = 141 </span>
3 0
3 years ago
2 · 32 + (3 · 2)2. i need the answer
vfiekz [6]

Answer: 76

Step-by-step explanation:

3 * 2 = 6

6* 2 = 12

2 * 32 = 64

12 + 64 = 76

4 0
3 years ago
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