Answer:
0.022 mol O
Explanation:
Mg3(Si2O5)2(OH)2
We can see that 1 mol of this substance has 3 mol of Mg.
Oxygen altogether is 5*2 (from (Si2O5)2) + 2(from(OH)2) = 10 +2 = 12
So, 1 mol of this substance has 12 mol oxygen.
So, 1 mol of this substance contains 3 mol Mg and 12 mol O, or
ratio Mg : O = 3 : 12 = 1 : 4
1 mol Mg ----- 4 mol O
0.055 mol Mg ---x mol O
x = 0.055*4/1 = 0.220 mol O
A) The mixing of a substance with another substance due to the motion or movement of its particles is called diffusion.
b) Gaseous particles tend to undergo diffusion because they have kinetic energy.
First you must write a balanced chemical equation.
C3H8 + 5O2 --> 3CO2 + 4H2O
From there, we can set up the stoichiometry equation to solve.
g O2= 70.2 g C3H8 X (1 mol C3H8/44.0962g C3H8) X (5 mol O2/1 mol C3H8) X (31.998g O2/1 mol O2)
Now solve, and you should get 254.7 g O2. Hope this helped!
