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3 years ago

If an atom has 29 electrons and a mass of 64, and it is neutral, what is the name of the atom?

Chemistry

1 answer:

jek_recluse [69]3 years ago

4 0

Explanation:

Copper has an atomic number of 29, so it contains 29 protons and 29 electrons. ... The atomic weight of copper is 64; it has 29 protons and 35 neutrons.

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Which is the larger atom As or P

sashaice [31]

Answer:

I think that As is larger

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3 years ago

11.

andrew11 [14]

B. Groups (families)

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4 years ago

Nickel and carbon monoxide react to form nickel carbonyl, like this: (s)(g)(g) At a certain temperature, a chemist finds that a

horsena [70]

The question is incomplete, here is the complete question:

Nickel and carbon monoxide react to form nickel carbonyl, like this:

$Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)$

At a certain temperature, a chemist finds that a 2.6 L reaction vessel containing a mixture of nickel, carbon monoxide, and nickel carbonyl at equilibrium has the following composition:

Compound Amount

Ni 12.7 g

CO 1.98 g

$Ni(CO)_4$ 0.597 g

Calculate the value of the equilibrium constant.

<u>Answer:</u> The value of equilibrium constant for the reaction is 2448.1

<u>Explanation:</u>

We are given:

Mass of nickel = 12.7 g

Mass of CO = 1.98 g

Mass of $Ni(CO)_4$ = 0.597 g

Volume of container = 2.6 L

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

$\text{Equilibrium concentration of nickel}=\frac{12.7}{58.7\times 2.6}=0.083M$

$\text{Equilibrium concentration of CO}=\frac{1.98}{28\times 2.6}=0.0272M$

$\text{Equilibrium concentration of }Ni(CO)_4=\frac{0.597}{170.73\times 2.6}=0.00134M$

For the given chemical reaction:

$Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)$

The expression of equilibrium constant for the reaction:

$K_{eq}=\frac{[Ni(CO)_4]}{[CO]^4}$

Concentrations of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

$K_{eq}=\frac{0.00134}{(0.0272)^4}\\\\K_{eq}=2448.1$

Hence, the value of equilibrium constant for the reaction is 2448.1

4 0

4 years ago

¿En qué grupo de sustancias químicas se incluye a la Hemoglobina?

olga2289 [7]

Answer:

"HEMOGLOBINA. Las características de la hemoglobina (Hb) como amortiguador están íntimamente vinculadas a la capacidad de disociación del grupo imidazólico del aminoácido histidina unido al hierro que contiene el grupo hemo (ver figura inferior)."

Link: http://www.ehu.eus/biomoleculas/buffers/buffer4.htm#:~:text=HEMOGLOBINA&text=Las%20caracter%C3%ADsticas%20de%20la%20hemoglobina,hemo%20(ver%20figura%20inferior).

3 0

3 years ago

Cho 200 g dung dịch NaCl 0,5M tác dụng hết với 400 ml AgNO3. Sau phản ứng thu được kết tủa và dung dịch không màu

ivolga24 [154]

Answer:

Explanation:

a. NaCl+ AgNO3-----> NaNO3+ AgCl

b. Số mol của NaCl= 0,2*0,5= 0,1 (mol)

------> Số mol của kết tủa AgCl tạo thành= 0,1 mol (dựa vào phương trình hóa học)

-----> Khối lượng của kết tủa AgCl tạo thành= 0,1*143,5=14,35(g)

c. Số mol của AgNO3= số mol của NaCl= 0,1 (mol)

------> Nồng độ mol của dd AgNO3 đã tham gia phản ứng= $\frac{0,1}{0,4}$ =0,25(M)

4 0

3 years ago