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2 years ago

A wave with a period of 0.008 second has a frequency of?

Physics

2 answers:

boyakko [2]2 years ago

8 0

As per the question the time period of the wave is 0.008 s.

we have to calculate the frequency of the wave.

Before going to calculate the frequency of the wave first we have to understand the frequency.

Frequency of a wave is defined as the number of waves passing through a point in unit time.

Time period of a wave means time taken by a wave for one complete vibration or oscillation.

The relation between frequency and wave is given as frequency is the reciprocal of time period.

Mathematically we can say $frequency[ f]=\frac{1}{T}$

$= \frac{1}{0.008s}$

=125 Hz [ans]

tatyana61 [14]2 years ago

6 0

The formula for frequency is f = 1/T where f is frequency and T is period in seconds.
You have you period which is 0.008s and that is all you will need to solve or frequency in a wave:
f = 1/2
f = 1/0.008s
f = 125Hz

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dem82 [27]

12.8 rad

Explanation:

The angular displacement $\theta$ through which the wheel turned can be determined from the equation below:

$\omega^2 = \omega_0^2 + 2\alpha\theta$ (1)

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$\omega_0 = 0$

$\omega = 34.7\:\text{rad/s}$

$\alpha = 47.0\:\text{rad/s}^2$

Using these values, we can solve for $\theta$ from Eqn(1) as follows:

$2\alpha\theta = \omega^2 - \omega_0^2$

$\theta = \dfrac{\omega^2 - \omega_0^2}{2\alpha}$

$\:\:\:\:= \dfrac{(34.7\:\text{rad/s})^2 - 0}{2(47.0\:\text{rad/s}^2)}$

$\:\:\:\:= 12.8\:\text{rad}$

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1 year ago

How much work is done when you push a crate horizontally with 130

Harrizon [31]

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You know the force in the direction of displacement (horizontally) and the displacement. So,

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A force of 8.0 N is along x direction, another force of 6.0 N is along +y direction. If both forces are acting on a point object

Darya [45]

Answer:

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Explanation:

It is given that,

Force acting along +x direction, $F_x=8\ N$

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Both the forces are acting on a point object located at the origin. Let the resultant force of the object is given by R. So,

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Here $\theta=90^{\circ}$

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