A wave with a period of 0.008 second has a frequency of?
2 answers:
As per the question the time period of the wave is 0.008 s.
we have to calculate the frequency of the wave.
Before going to calculate the frequency of the wave first we have to understand the frequency.
Frequency of a wave is defined as the number of waves passing through a point in unit time.
Time period of a wave means time taken by a wave for one complete vibration or oscillation.
The relation between frequency and wave is given as frequency is the reciprocal of time period.
Mathematically we can say
=125 Hz [ans]
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Answer:
15.8 V
Explanation:
The relationship between capacitance and potential difference across a capacitor is:
where
q is the charge stored on the capacitor
C is the capacitance
V is the potential difference
Here we call C and V the initial capacitance and potential difference across the capacitor, so that the initial charge stored is q.
Later, a dielectric material is inserted between the two plates, so the capacitance changes according to
where k is the dielectric constant of the material. As a result, the potential difference will change (V'). Since the charge stored by the capacitor remains constant,
So we can combine the two equations:
and since we have
V = 71.0 V
k = 4.50
We find the new potential difference: