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jek_recluse [69]
3 years ago
7

Suppose multiple stations are connected in wired network where CSMA/CD implemented. Among them, station A wants to communicate w

ith B and station C wants to communicate with D. Previously, both of these sender stations have faced collisions at different timings and are still unsuccessful in their transmission. The value of k for station A has reached to 6, whereas the value of k for station B has reached to 4. The maximum attempts allowed to any station is set to 10 and transmission time for a frame is 0.5ms.
This time, Both of the sender stations (A & C) sensed the medium, both got the channel idle and started transmission. Sooner, the station A detected the collision.
i.What will happen now?
ii.How long station A has wait before re-trying
iii.Meanwhile what will happen at station C
Physics
1 answer:
anastassius [24]3 years ago
6 0

Answer:

bro i think ur from the uni of arid agriculture rawalpindi and today is your networking paper

Explanation:

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John and Caroline go out for a walk one day. This graph represents their distance from home.
Serga [27]

Answer:

Option C is the correct answer.

Explanation:

  We have velocity of a body = Change in position/ Time.

  Considering first portion of graph,

  Change in position = 30 - 0 = 30 m

  Time = 0.75 hours = 45 minutes = 2700 seconds

   Velocity = 30/2700 = 0.011 m/s

  Considering second portion of graph,

  Change in position = 30 - 30 = 0 m

  Time = 0.5 hours = 30 minutes = 1800 seconds

   Velocity = 0/1800 = 0 m/s

 Considering third portion of graph,

  Change in position = 0 - 30 = -30 m

  Time = 0.75 hours = 45 minutes = 2700 seconds

   Velocity = -30/2700 = -0.011 m/s

So firstly they walked in one direction(positive direction), then they were still(velocity is zero), then they walked in the opposite direction( velocity is negative).

Option C is the correct answer.

3 0
3 years ago
Read 2 more answers
An electromagnet is strong enough to lift 200 kg of mass. If you double the number of turns of wire around the core and triple t
VLD [36.1K]

Answer:1200 kg

Explanation:

Given

Electromagnet can lift a mass of  200\ kg

Magnetic force necessary to hold mass is proportional to Magnetic field

and magnetic field (B) is proportional to NIA

where N=no of turns

I=current in the magnet

A=area of cross-section

When we double the no of turns and triple the current then

N becomes 2 N

I becomes 3 I

therefore magnetic field becomes 6 times

Thus magnetic force becomes 6 times and we can say that electromagnet can hold the 6 times of given weight

i.e. 6\times 200=1200\ kg

4 0
3 years ago
24 grams of magnesium metal reacts with 16 grams of oxygen gas to form magnesium oxide. according to the law of conservation of
wariber [46]

The mass of magnesium oxide must be 40 grams

Explanation:

The law of conservation of mass states that the total mass of the reactant in a chemical reaction must be equal to the total mass of the products after the reaction has completed.

In this problem, we have:

Reactants:

Magnesium metal (mass: 24 grams)

Oxygen gas (mass: 16 grams)

Products:

Magnesium oxide (mass: ?)

According to the law of conservation of mass, the mass of the magnesium oxide must be equal to the sum of the mass of the magnesium metal and the oxygen gass. Therefore:

Mass (magnesium oxide) = 24 g + 16 g = 40 g

Learn more about law of conservation of mass:

brainly.com/question/5017646

#LearnwithBrainly

8 0
3 years ago
Will increasing length and cross-sectional area increase the resistance of an object?
Klio2033 [76]

Answer:

Increasing length increases resistance

increasing cross sectional area reduces the resistance

.

Explanation:

The formula for resistance of an object is

r = d \frac{l}{a}

where r is resistance, d is resistivity of the material, l is length of material and a is cross sectional area of the object. This equation shows us that resistance is directly proportional to length and inversely proportional to cross sectional area. Hence, increasing length increases resistance while increasing cross sectional area reduces the resistance.

If these 2 variables are varied to the same extent, the net effect can be zero on the resistance.

5 0
2 years ago
Professional baseball pitchers deliver pitches that can reach the blazing speed of 100 mph (miles per hour). A local team has dr
Wittaler [7]

Answer:

A. ) K =126. 7 J

B. ) h= 91.1 m.

Explanation:

A)

  • Assuming no air resistance, once released by the pitcher, the speed must keep constant through all the trajectory, so the kinetic energy of the ball can be expressed as follows:

       K = \frac{1}{2}*m*v^{2}  =  \frac{1}{2}*0.142 kg*(42.24m/s)^{2} = 126.7 J (1)

B)

  • Neglecting air resistance, total mechanical energy must be the same at any point, so, if we choose the ground level as the zero reference level for the gravitational potential energy, and assuming that the ball attains this kinetic energy just before striking ground, this value must be equal to the gravitational potential energy just before be dropped, so we can write the following equality:

        U_{o} = K_{f} = 126. 7 J (2)

        ⇒ m*g*h = 126. 7 J

  • Solving for h, we get:

       h = \frac{K_{f}}{m*g} = \frac{126.7J}{0.1420kg*9.8m/s2} = 91.1 m (3)

4 0
2 years ago
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