Answer: 4.9 x 10-3 N
Explanation:
A = 500cm^2 = 5 x 10^-2 m^2
V = 5 m/s
R = 10^-3 g/cm^2.sec = 10^-2kg/m^2 . sec
Prain water = R / V = 10^-2 / 5 = 2 x 10-3 kg/m^3
For the stationary bowl,
dm/dt =pAv= RA
F= dp/dt = (dm/dt) v = RAv = 2.5 x 10^-3 N
Bowl moving upwards to speed u = 2 m/s
dm/dt = pA ( v + u) / v
F = dp/dt = (dm/dt)(v+u) = RA (v+u)^2 / v = 4.9 x 10^-3 N
The unconditioned stimulus (UCS) for Tab the dog is: B. The flowers and fence.
<h3>The types of stimuli.</h3>
In Science, the two (2) stimuli that are repeatedly paired in classical conditioning include:
<h3>What is an unconditioned stimulus?</h3>
An unconditioned stimulus can be defined as a stimulus that is capable of naturally triggering a response, before or without any conditioning while it elicit a specific response without learning.
- This ultimately implies that, an unconditioned stimulus leads to an automatic response in a living organism such as a dog.
In this scenario, the unconditioned stimulus (UCS) for Tab the dog is simply the flowers and fence.
Read more on unconditioned stimulus here: brainly.com/question/24868138
Answer:
6.0cm
Explanation:
Given
focal length = 15.0cm
object distance = 10.0cm
Required
Image distance v
Using the formula
1/f = 1/u + 1/v
1/15 = 1/10+1/v
1/v = 1/15 + 1/10
1/v = 2+3/30
1/v = 5/30
v = 30/5
v = 6.0cm
Hence the image distance is 6.0cm
